python--查询员工信息
# cat user.txt1 cheeron python 4099822
2 forilen shell 12309865
3 XueLi JS 4321780
4 LiLei IT 48393022
5 Simith IT 2340987
6 Liudehua Python 1234567
7 cheeron python 4099822
8 forilen shell 12309865
9 XueLi JS 4321780
10 LiLei IT 48393022
11 Simith IT 2340987
12 Liudehua Python 1234567
#!/usr/bin/env python
staff_list = 'user.txt'
f = open(staff_list)
c = f.readlines()
while True:
user_input = raw_input('\033[32;1mPls input sth to search:\033[0m ').strip()
if len(user_input) == 0: continue
for line in c:
if user_input in line:
print line
break
else:
print '\033[31;1mnot a vaild input!\033[0m'
解决1次只匹配单行的问题，增加一个key，作为信号量，当匹配时则为key赋值为1，否则为0.
1 #!/usr/bin/env python
2 staff_list = 'user.txt'
3 f = open(staff_list)
4 c = f.readlines()
5 while True:
6 user_input = raw_input('\033[32;1mpls input sth to search:\033[0m ').strip()
7 if len(user_input) == 0:continue
8 key=0
9 for line in c:
10 if user_input in line:
11 print line
12 key=1
13 if key == 0:
14 print '\033[31;1mnot a vaild key word!\033[0m'
结果：
pls input sth to search: LiLei
4 LiLei IT 48393022
10 LiLei IT 48393022
pls input sth to search:
页:
[1]