python 多级菜单进入城市
python 多级菜单
可实现功能有：进入子菜单 返回上一级菜单 退出菜单 帮助
#/usr/bin/env python3
# -*- encoding: utf-8 -*-
# Auther:yooma 2016-08-14 22:00
import sys
execLaye = {1:{"北京":{1:{"东城":{1:{"建国门":{1:"建国门大厦",2:"门建国大厦"}},2:{"东单":{1:"东单大厦",2:"单东大厦"}}}
},
2:{"西城":{1:{"阜成门":{1:"四川大厦",2:"中基大厦"}},2:{"西直门":{1:"沸腾鱼",2:"西直门桥"}}}
},
}
},
2:{"上海":{1:{"浦东":{1:{"浦东一":{1:"浦东一大厦",2:"浦东一一大厦"}},2:{"浦东二":{1:"浦东二大厦",2:"浦东二二大厦"}}}
},
2:{"东环":{1:{"东环一":{1:"东环一大厦",2:"东环一一大厦"}},2:{"东环二":{1:"东环二大厦",2:"东环二二大厦"}}}
}
},
},
}
def help():
print('''
Useage:
1. [ h ]-- help to useaga.
2. [ 1 | 2 ] -- Input city number selected into it.
3. [ b ]-- "b" parameter function is to return to the previous level menu.
4. [ q | quit | exit ] -- function is exit current program.
''')
def select(value, record):
city = ""
for k, v in value.items():
if isinstance(v,str):
city = city + '\t' + str(k) + '.' + ' %s\n' % v
else:
city = city + '\t' + str(k) + '.' + ' %s\n' % list(v.keys())
# SelectCity = input("%sSelect please: " % city)
while 1:
SelectCity = input("%sSelect please: " % city)
if SelectCity == 'h':
help()
# sys.exit(0)
for n, i in value.items():
if SelectCity == str(n):
if isinstance(i,str):
print("~~~~~~~Welcome to %s ~~~~~~~" % i)
sys.exit(0)
else:
print("[ Welcome to %s ]" % list(i.keys()))
select(list(i.values()), value)
elif SelectCity == 'b':
select(record, record)
elif SelectCity == 'q' or SelectCity == 'quit' or SelectCity == 'exit':
sys.exit(0)
else:
continue
if __name__ == "__main__":
select(execLaye,execLaye)
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