python 利用random的shuffle洗牌方法生产1个12位数的随机密码
1 # !/usr/bin/env python
2 # -*- coding:utf-8 -*-
3 import random
4
5 schr =
6 bchr =
7 num =
8 signs = ['!','@','#','$','%','^','&','*','(',')','+','-','_','=','<','>','`','|','[',']','{','}','?','/']
9 codes = schr + bchr + num + signs
10
11 def shuffle(codes):
12 for i in range(5):
13 random.shuffle(codes)
14 return codes
15
16 def get_code(codes):
17 codes = shuffle(codes)
18 rand_start = random.randint(0,len(codes)-12)
19 rand_end = rand_start + 12
20 return ''.join(codes)
21
22 print get_code(codes)
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