janneyabc 发表于 2016-10-31 05:33:02

SQL Server中时间比较

select count(*) from table where DATEDIFF (, '2004-09-18 00:00:18', '2004-09-18 00:00:19')> 0

说明

　　selectDATEDIFF(day, time1 , time2)    对应示例语句如下

　　selectDATEDIFF(day, '2010-07-23 0:41:18', '2010-07-23 23:41:18')

　　time1 > time2 为负数;

　　time1 < time2 为正数;

　　 :只会比较 2010-07-23 忽略 0:41:18' 其他同理

以下分别:

　　年: SELECT DATEDIFF(,time1 , time2)

　　月: SELECT DATEDIFF(, time1 , time2)

　　天: SELECT DATEDIFF(, time1 , time2)

　　小时: SELECT DATEDIFF(, time1 , time2)

　　秒: SELECT DATEDIFF(, time1 , time2)
页: [1]
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