soyizi 发表于 2017-1-11 08:04:49

Apache+tomcat+jk处理请求的简单流程

  请求流程
1.根据servername找到对应的虚拟主机
2.如果不是JkMount找定的路径则由Apache直接处理
3.如果是则找到对应的worker(这一行后面的worker)
4.通过workers.properties找到worker绑定的服务器和端口(然后由此服务器处理)
  有问题?直接google!<script type="text/javascript"><!--google_ad_client = "pub-0757178726455256";google_ad_format = "js_sdo";google_cts_mode ="rs";google_num_cts = "2";google_searchbox_width = 215;google_searchbox_height = 26;google_link_target = 2;google_logo_pos = "left";google_rs_pos = "right";google_ad_height = 35;google_ad_width = 760;// --></script><script src="http://pagead2.googlesyndication.com/pagead/show_sdo.js" type="text/javascript"></script>
  <script type="text/javascript"><!--google_ad_client = "pub-0757178726455256";/* 728x90, 创建于 09-6-17 */google_ad_slot = "1633515232";google_ad_width = 728;google_ad_height = 90;// --></script><script src="http://pagead2.googlesyndication.com/pagead/show_ads.js" type="text/javascript"></script>
页: [1]
查看完整版本: Apache+tomcat+jk处理请求的简单流程