5imobi 发表于 2017-2-8 11:42:41

Ajax与Servlet ,Tomcat结合分析与测试

<script type='text/javascript'>
//实现功能,对用户名是否被注册进行验证
//验证时间onblur
//服务器是tomacat与servlet结合作为服务器端
//浏览器在ff与chrome下测试,版本应就是近期才装的
//服务器端假设各位已会
//ajax函数
var ajax=function(url){
var xhr=null;
if(window.XMLHttpRequest){
xhr=new XMLHttpRequest();
}else{
xhr=new ActiveXObject("Microsoft.XMLHTTP");
}
xhr.open("get", url, true);
xhr.send();
xhr.onreadystatechange=function(){
if(xhr.readyState==4 && xhr.status==200){
//console.info(xhr.responseText);
//console.info(xhr.responseXML);//为null
alert(xhr.responseText);
}
};
};
window.onload=function(){
var oInputs=document.getElementsByTagName('input');
var url="AjaxServlet?userName="+oInputs.value;
oInputs.onblur=function(){
ajax(url);
};
};
</script>
</head>
<body>
<form action="">
userName<input type="text" name="userName"/><br/>
password<input type='text' name="passWord"/>
</form>
</body>

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
response.setCharacterEncoding("UTF-8");
String s1=request.getParameter("userName");
if(s1.equals("userName")){
PrintWriter out = response.getWriter();
out.print("名字相同111");
out.flush();
out.close();
}else{
PrintWriter out = response.getWriter();
out.print("success");
out.flush();
out.close();
}
}


<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>AjaxServlet</servlet-name>
<servlet-class>hyl.AjaxServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>AjaxServlet</servlet-name>
<url-pattern>/AjaxServlet</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
  //给上结果图

 
页: [1]
查看完整版本: Ajax与Servlet ,Tomcat结合分析与测试