jxdiscuz 发表于 2017-2-18 06:33:38

weblogic配置修改代码后不需要重启热部署方式

  我用的是weblogic11g 在项目的web-info中创建weblogic.xml
  ----------将一下内容复制到weblogic.xml中-----------
  <!DOCTYPE weblogic-web-app PUBLIC "-//BEA Systems, Inc.//DTD Web Application 8.1//EN" "http://www.bea.com/servers/wls810/dtd/weblogic810-web-jar.dtd">
<weblogic-web-app>
<session-descriptor>
    <session-param>
   <param-name>TimeoutSecs</param-name>
   <param-value>300</param-value>
    </session-param>
    <session-param>
<param-name>CookieName</param-name>
<param-value>写自己的项目部署文件名</param-value>
</session-param>
    </session-descriptor>
<jsp-descriptor>
    <jsp-param>
      <param-name>keepgenerated</param-name>
      <param-value>true</param-value>
    </jsp-param>
    <jsp-param>
      <param-name>debug</param-name>
      <param-value>true</param-value>
    </jsp-param>
    <jsp-param>
       <param-name>pageCheckSeconds</param-name>
       <param-value>0</param-value>
    </jsp-param>
</jsp-descriptor>

<container-descriptor>
   <servlet-reload-check-secs>-1</servlet-reload-check-secs>
   <!--<prefer-web-inf-classes>true</prefer-web-inf-classes>-->
</container-descriptor>

<charset-params>
    <input-charset>
      <resource-path>/*</resource-path>
      <java-charset-name>utf-8</java-charset-name>
    </input-charset>
</charset-params>
<context-root>写自己项目的部署文件名</context-root>
</weblogic-web-app>
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