jQuery JSON with PHP json_encode and json_decode
<!----><!---->http://code.google.com/p/jquery-json/
Today I looked for a replacement for my old
jspanserializer.js script that I can’t even remember where I found
anymore. Turns out that I wont have to either, I can forget it. From
now on I’ll use jQuery JSONinstead.
This stuff can really not get any simpler than this:
<html
>
<head
>
<title
>
Json Test</title>
<SCRIPT
src
="jquery.js"
>
</SCRIPT>
<SCRIPT
src
="jquery.json.js"
>
</SCRIPT>
<script
>
$(document
).ready(function
(){
var
data = new
Object();
data.hello = "Hello"
;
data.world = 'World'
;
data.worked = " it worked "
;
data.somebool = true
;
data.array = new
Array("he\"ll\"o"
, '"World"'
);
var
dataString = $.toJSON(data);
$.post('phpfile.php'
, {data: dataString}, function
(res){
var
obj = $.evalJSON(res);
if
(obj.somebool === true
)
$("#result"
).html(obj.hello + ' '
+ obj.array[1
] + obj.worked + ". Message from PHP: "
+obj.php_message);
});
});
</script>
</head>
<body
>
<div
id
="result"
>
</div>
</body>
</html>
We initialize some test data, encode it with $.toJSONand send it with $.postto phpfile.php
:
$
res
= json_decode($_REQUEST
['data'
], true
);
$
res
["php_message"
] = "I am PHP"
;
echo
json_encode($
res
);
Note the last argument to json_decode
,
omitting it will result in a return type of stdObject which is not what
we want in this simple test. Note that json_decode requires PHP 5.2. If
that is not available you might want to check out an alternative method.
And the final output in the result div:
Hello "World" it worked . Message from PHP: I am PHP
Great!
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