两个Python练习题
1．假设校园电费是0.6元/千瓦时，输入这个月使用了多少千瓦时的点，算出你要交的电费。假如你只有1元和1毛的硬币，请问各需要多少1元和1毛的硬币。
输入输出：
输入这个月使用的电量：11
电费：6.6
共需6张1元和6张1毛
def main():
pq = input('please input the power quantity:')
price = 0.6
amt = pq * price * 10
i = int(amt) / 10
j = int(amt) % 10 / 1
print 'It will spend you %d yuan and %d jiao' % (i,j)
>>> main()
please input the power quantity:32
It will spend you 19 yuan and 1 jiao
2.假设已加密系统采用替换法进行加密，替换的规则如下：
明文 a b c d e f g h i j k l m n o p q r s t u v w x y z
密文 q w e r t y u i o p a s d f g h j k l z x c v b n m
设计一程序，输入一串明文，输出它对应的密文
1.使用find
def decode():
strKey = 'abcdefghijklmnopqrstuvwxyz'
strValue = 'qwertyuiopasdfghjklzxcvbnm'
strIn = raw_input('please enter some words:')
strOut = ''
for i in range(len(strIn)):
strOut += strValue)]
print 'decode result is :%s' % (strOut)
>>> decode()
please enter some words:abcefeg
decode result is :qwetytu
2.使用字典
def docode():
strKey = 'abcdefghijklmnopqrstuvwxyz'
strValue = 'qwertyuiopasdfghjklzxcvbnm'
strIn = raw_input('please enter some words:')
dictDecode = {}
strOut = ''
for i in range(len(strKey)):
dictDecode] = strValue
for i in range(len(strIn)):
strOut += dictDecode]
print 'decode result is :%s' % (strOut)
>>> decode()
please enter some words:helloworld
decode result is :itssgvgksr
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