python 学习笔记一
#coding=UTF-8
'''
Created on 2011-5-18
@author: lingyibin
'''
import types
import math
print 'hello'
#append
a =
a.append()
print a
print a;
#extend
a =
a.extend()
print a
#pop
a.pop()
print a
a.pop(2)
print a
#长度
print len(a)
#算出元素在list中出现的次数
print a.count(4)
#算出元素在list中的位置
print a.index(4)
'''
4
]
6
1
2
'''
# list的反转
a.reverse()
print a
# 用list来模拟栈
a = []
a.append(0)
a.append(3)
a.append(5)
a.pop()
print a
# 用list来模拟队列
a = []
a.append(0)
a.append(3)
a.append(5)
a.pop(0)
print a
#用list来模拟树
leaf1 =
leaf2 =
leaf3 =
leaf4 =
branch1 =
branch2 =
root =
print root
#把字符串按一定的格式输出
a=["123","456","abc","Abc","AAA"]
k =
print k#['123', '456', 'abc', 'Abc', 'AAA']
#得到a中仅由字母组成的字条串，并把它变成大写
k =
print k#['ABC', 'ABC', 'AAA']
k = [ k.lower() for k in a if k.isupper() ]
print k#['aaa']
k =
print k#
a=
k =
print k
b = """Hello , I am lingyibin.
nice to meet you!\a"""
print b
#把句子格式化，即开头大写
c = "THIS IS A SENTENCE！".capitalize() #This is a sentence！
print c
#大小写互换
print c.swapcase()
#字符串查找
print c.index("is") #2
print c.rindex("is") #反向查找，结果5
c = "ok abc abc abc"
print c.find("abc",7) #从7的位置开始查找,结果#7
print c.find("abc",4,9) #4到9的位置查找，不包含9，结果－1
print c.count("abc") #算字符串出现了几次，结果3
#按格式打印
print "%s is good,he he ,%d" % ("Food",2) #这里，在linux下，注意％与%的差别
print "%s’s height is %dcm"%("Charles",180)
#转为8进制
print "%d is %o or %#o"%(16,16,16)
#转为16进制
print "%d is %x or %#x"%(16,16,16)
#科学表示法
print "%e"%(1000) #1.000000e+03
print "%E"%(1000) #1.000000E+03
#字符转数字，数字转字符
print "%c"%(68)
print ord('0')
print ord('A')
print ord('a')
print chr(ord('d')+5)
#固定字符打印。
print "hello".ljust(10)
print "hello".rjust(10)
print "hello".center(10)
print "hello".center(10).lstrip() #去掉左边的空格
print "hello".center(10).rstrip() #去掉右边的空格
print "hello".center(10).strip() #去掉两边的空格
#分解与组合
print "\t".join(["Hello","World","Python","Said"]) #Hello World Python Said
print " ".join("Hello World Python Said".split()) #Hello World Python Said
#元组
a,b=(1,2)
print a,b #1 2
#巧妙地互换
b,a=a,b
print a,b #2 1
#用in来查找
str="abcd"
if "a" in str: print " ok "
x=12
l=
if x in l : print "x is in l"
#取部分元素打印。
print str #bcd
print l#
print l*2 #
pricelist={"clock":12,"table":100,"xiao":100 }
print pricelist["clock"] #12
del pricelist["clock"]
print pricelist
print pricelist.items() #[('table', 100), ('xiao', 100)]
print pricelist.values() #
print pricelist.keys() #['table', 'xiao']
# tuple中有两个元素，一个是key,一个是value
pricelist=dict([("clock",12),("table",100),("xiao",100)])
print pricelist
#加入一个元素
pricelist["apple"]=12
print pricelist #{'table': 100, 'apple': 12, 'xiao': 100, 'clock': 12}
#复制
a = pricelist.copy()
print a#{'table': 100, 'clock': 12, 'apple': 12, 'xiao': 100}
b = pricelist
a["cool"] = 101
print pricelist #{'table': 100, 'apple': 12, 'xiao': 100, 'clock': 12}
#下面的是直接引用。
b["cool"] = 101
print pricelist #{'table': 100, 'cool': 101, 'apple': 12, 'xiao': 100, 'clock': 12}
# print pricelist["pear"] #报错
print pricelist.get("pear") # 打印None
print pricelist.has_key("pear") #False
pricelist.clear()
pricelist=dict([(x,10*x) for x in ])
print pricelist
print range(1,10,2) #
#乘方和n次方根
print 2**10 #1024
print 27**(1.0/3)
print math.pow(1024, 1.0/10)
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