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花花世界蕾 发表于 2017-5-4 11:53:34

"To sort a dictionary" (Python recipe)

　　## {{{ http://code.activestate.com/recipes/52306/ (r2)
# (IMHO) the simplest approach:
def sortedDictValues1(adict):
    items = adict.items()
    items.sort()
    return

# an alternative implementation, which
# happens to run a bit faster for large
# dictionaries on my machine:
def sortedDictValues2(adict):
    keys = adict.keys()
    keys.sort()
    return for key in keys]

# a further slight speed-up on my box
# is to map a bound-method:
def sortedDictValues3(adict):
    keys = adict.keys()
    keys.sort()
    return map(adict.get, keys)
## end of http://code.activestate.com/recipes/52306/ }}}

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