lipeng 发表于 2017-5-4 13:05:01

匹配次数python os 库 匹配次数

  在写这篇文章之前,xxx已经写过了几篇关于改匹配次数主题的文章,想要了解的朋友可以去翻一下之前的文章
  >>>
  import
  os
  >>>
  os.getcwd()
  >>>
  os.chdir(’..’)
  >>>os.listdir(’/home/sb/bioinfo/
  seqs’)
  >>>os.path.isfile(’/home/
  sb’)
  >>>os.path.isdir(’/home/
  sb’)
  >>>os.remove(’/home/sb/bioinfo/seqs/
  ms115.ab1’)
  >>>os.rename(’/home/sb/seqs/readme.txt’,’/home/sb/
  Readme’)
  >>>os.mkdir(’/home/sb/processed-
  seqs’)
  >>>os.path.join(os.getcwd(),
  "
  images
  "
  )
  >>>os.path.exists(os.path.join(os.getcwd(),
  "
  images
  "
  ))
  #
  Checksifgiven path exists
  >>>os.path.split(’/home/sb/seqs/ms2333.ab1’)
  #
  (’/home/sb/seqs’,’ms2333.ab1’)
  >>>os.path.splitext(’/home/sb/seqs/ms2333.ab1’)
  #
  (’/home/sb/seqs/ms2333’,’.ab1’)
  for
  x
  in
  os.listdir(mypath):
  if
  os.path.splitext(x) ==
  ’.fas’: fh
  =
  open(os.path.join(mypath,x),’U’)
  >>>
  import
  xml.etree.ElementTreeasET
  >>>tree=ET.parse(
  "
  /home/sb/bioinfo/smallUniprot.xml
  "
  )
  >>>
  import
  sys
  >>>
  sys.path
  >>>sys.path.append(
  "
  /home/sb/MyPyModules
  "
  )
  #
  正则抒发
  >>>
  import
  re
  >>>mo=re.search(
  "
  hello
  "
  ,
  "
  Helloworld,helloPython!
  "
  )
  >>>mo.group()
  #
  ’hello’ group() returns the string matched by the REGEX
  >>>mo.span()
  #
  (13,18) span() returns a tuple containing the(start,end)
  #
  positions of the match
  >>>text.index(
  "
  hello
  "
  )
  >>>re.findall(
  "
  ello
  "
  ,
  "
  Helloworld,helloPython,!
  "
  )
  #
  findall
  >>>mos=re.finditer(
  "
  ello
  "
  ,
  "
  Helloworld,helloPython,!
  "
  )
  >>>rgx=re.compile(
  "
  ello
  "
  )
  >>>rgx.findall(
  "
  Helloworld,helloPython,!
  "
  )
  >>>rgx.search(
  "
  Helloworld,helloPython,!
  "
  )
  >>>rgx.match(
  "
  Helloworld,helloPython,!
  "
  )
  >>>rgx.findall(
  "
  Helloworld,helloPython,!
  "
  )
  #
  sub(rpl,str[,count=0])
  >>>rgx.sub(
  ""
  ,seq)
  >>>rgx.subn(
  ""
  ,seq)
  #
  subn(rpl,str[,count=0]): 匹配次数
  文章结束给大家分享下程序员的一些笑话语录: 问答
Q:你是怎么区分一个内向的程序员和一个外向的程序员的? A:外向的程序员会看着你的鞋和你说话时。
Q:为什么程序员不能区分万圣节和圣诞节? A:这是因为 Oct 31 == Dec 25!(八进制的 31==十进制的 25)
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