wanmin444 发表于 2017-5-8 09:02:37

零基础学python-8.3 列表的索引、分片和矩阵

  索引:
  注意:如果超出长度,则报错
  如果索引为负数,则取数的方向反转

>>> aList=['123',123,123.0]
>>> aList
'123'
>>> aList
123.0
>>> aList[-2]
123
>>> aList[-3]
'123'
>>> aList
Traceback (most recent call last):
File "<pyshell#25>", line 1, in <module>
aList
IndexError: list index out of range


  分片:
  注意:如果是负数,取值会出现变化

>>> aList=['123',123,123.0]
>>> aList
['123']
>>> aList

>>> aList
['123', 123, 123.0]
>>> aList[-1:4]

>>> aList[-1:0]
[]
>>> aList[-1:1]
[]
>>>

>>> aList[-1:5]

>>> aList[-1:7]

>>> aList[-3:4]
['123', 123, 123.0]
>>>


  矩阵:类似于java的多维数组

>>> matrix=[,['a','b'],[('ttt')]]
>>> matrix
['a', 'b']
>>> matrix
'ttt'
>>> matrix
'b'
>>>


就说到这里,谢谢大家


------------------------------------------------------------------

点击跳转零基础学python-目录




版权声明:本文为博主原创文章,未经博主允许不得转载。
页: [1]
查看完整版本: 零基础学python-8.3 列表的索引、分片和矩阵