python开发_calendar
如果你用过linux，你可能知道在linux下面的有一个强大的calendar功能，即日历在python中，同样也有这样的一个强大的calendar
下面是我做的demo：
1 #python中的calendar
2
3 import calendar
4
5 #返回指定年的某月
6 def get_month(year, month):
7 return calendar.month(year, month)
8
9 #返回指定年的日历
10 def get_calendar(year):
11 return calendar.calendar(year)
12
13 #判断某一年是否为闰年，如果是，返回True，如果不是，则返回False
14 def is_leap(year):
15 return calendar.isleap(year)
16
17 #返回某个月的weekday的第一天和这个月的所有天数
18 def get_month_range(year, month):
19 return calendar.monthrange(year, month)
20
21 #返回某个月以每一周为元素的序列
22 def get_month_calendar(year, month):
23 return calendar.monthcalendar(year, month)
24
25 def main():
26 year = 2013
27 month = 8
28 test_month = get_month(year, month)
29 print(test_month)
30 print('#' * 50)
31 #print(get_calendar(year))
32 print('{0}这一年是否为闰年？：{1}'.format(year, is_leap(year)))
33 print(get_month_range(year, month))
34 print(get_month_calendar(year, month))
35
36 if __name__ == '__main__':
37 main()
运行效果：
Python 3.3.2 (v3.3.2:d047928ae3f6, May 16 2013, 00:03:43) on win32
Type "copyright", "credits" or "license()" for more information.
>>> ================================ RESTART ================================
>>>
August 2013
Mo Tu We Th Fr Sa Su
1234
56789 10 11
12 13 14 15 16 17 18
19 20 21 22 23 24 25
26 27 28 29 30 31
##################################################
2013这一年是否为闰年？：False
(3, 31)
[, , , , ]
>>>
再附上calendar.py的源码：
1 """Calendar printing functions
2
3 Note when comparing these calendars to the ones printed by cal(1): By
4 default, these calendars have Monday as the first day of the week, and
5 Sunday as the last (the European convention). Use setfirstweekday() to
6 set the first day of the week (0=Monday, 6=Sunday)."""
7
8 import sys
9 import datetime
10 import locale as _locale
11
12 __all__ = ["IllegalMonthError", "IllegalWeekdayError", "setfirstweekday",
13 "firstweekday", "isleap", "leapdays", "weekday", "monthrange",
14 "monthcalendar", "prmonth", "month", "prcal", "calendar",
15 "timegm", "month_name", "month_abbr", "day_name", "day_abbr"]
16
17 # Exception raised for bad input (with string parameter for details)
18 error = ValueError
19
20 # Exceptions raised for bad input
21 class IllegalMonthError(ValueError):
22 def __init__(self, month):
23 self.month = month
24 def __str__(self):
25 return "bad month number %r; must be 1-12" % self.month
26
27
28 class IllegalWeekdayError(ValueError):
29 def __init__(self, weekday):
30 self.weekday = weekday
31 def __str__(self):
32 return "bad weekday number %r; must be 0 (Monday) to 6 (Sunday)" % self.weekday
33
34
35 # Constants for months referenced later
36 January = 1
37 February = 2
38
39 # Number of days per month (except for February in leap years)
40 mdays =
41
42 # This module used to have hard-coded lists of day and month names, as
43 # English strings.The classes following emulate a read-only version of
44 # that, but supply localized names.Note that the values are computed
45 # fresh on each call, in case the user changes locale between calls.
46
47 class _localized_month:
48
49 _months =
50 _months.insert(0, lambda x: "")
51
52 def __init__(self, format):
53 self.format = format
54
55 def __getitem__(self, i):
56 funcs = self._months
57 if isinstance(i, slice):
58 return
59 else:
60 return funcs(self.format)
61
62 def __len__(self):
63 return 13
64
65
66 class _localized_day:
67
68 # January 1, 2001, was a Monday.
69 _days =
70
71 def __init__(self, format):
72 self.format = format
73
74 def __getitem__(self, i):
75 funcs = self._days
76 if isinstance(i, slice):
77 return
78 else:
79 return funcs(self.format)
80
81 def __len__(self):
82 return 7
83
84
85 # Full and abbreviated names of weekdays
86 day_name = _localized_day('%A')
87 day_abbr = _localized_day('%a')
88
89 # Full and abbreviated names of months (1-based arrays!!!)
90 month_name = _localized_month('%B')
91 month_abbr = _localized_month('%b')
92
93 # Constants for weekdays
94 (MONDAY, TUESDAY, WEDNESDAY, THURSDAY, FRIDAY, SATURDAY, SUNDAY) = range(7)
95
96
97 def isleap(year):
98 """Return True for leap years, False for non-leap years."""
99 return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)
100
101
102 def leapdays(y1, y2):
103 """Return number of leap years in range [y1, y2).
104 Assume y1
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