半只蚂蚁 发表于 2018-9-28 08:42:56

mysql帮助文档学习

  select * from t1, t2 where t1.id = t2.id;
  mysql -h host -u user -p
  quit
  select version(), current_date;
  select sin(pi()/4), (4+1)/5;
  select version();
  select now();
  select user(), current_date;
  \c(取消前面输入的)
  select * from my_table where name = 'Smith' and age < 30;
  show databases;
  use test(use 和quit不用分号)
  grant all on menagerie .* to 'your_mysql_name'@'your_client_host'; (不解)
  create datebase menagerie;
  use menagerie
  mysql -h host -u user -p menagerie
  show tables;
  create table pet (name varchar(20), owner varchar(20),
  species varchar(20), sex char(1), birth date, death date);
  show tables;
  describe pet;
  load data local infile '/path/pet.txt' into table pet;
  insert into pet values ('puff', 'Diane','hamster','f','1990-12-11',NULL);
  select what from table where conditions;
  select * from pet;
  delete from pet;
  load data local infile 'pet.txt' into table pet;
  update pet set birth = '1998-12-11' where name = 'Bowser';
  select * from pet where species = 'snake' or species = 'bird';
  select * from pet where (species = 'cat' and sex = 'm') or (species = 'dog' and sex = 'f');
  select name, birth from pet;
  select distinct owner from pet;
  select name, species, birth from pet where species ='dog' or species = 'cat';
  select name from pet order by birth desc;
  select name, species, birth from pet order by species, birth desc;(desc只影响birth,不影响species)
  select name, curdate(),(year(curdate())-year(birth))-(right(curdate(),5)
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