mysql练习题
练习：导入hellodb.sql生成数据库(1) 在students表中，查询年龄大于25岁，且为男性的同学的名字和年龄；
MariaDB > select Name,Age from students where Age>25 and Gender='M';
(2) 以ClassID为分组依据，显示每组的平均年龄；
MariaDB > select> (3) 显示第2题中平均年龄大于30的分组及平均年龄；
MariaDB > select> (4) 显示以L开头的名字的同学的信息；
MariaDB > select * from students where Name like 'L%';
MariaDB > select * from students where Name rlike '^L';
（5) 显示TeacherID非空的同学的相关信息；
MariaDB > select * from students where TeacherID is NOT NULL;
(6) 以年龄排序后，显示年龄最大的前10位同学的信息；
MariaDB > select * from students order by Age desc limit 10;
(7) 查询年龄大于等于20岁，小于等于25岁的同学的信息；用三种方法；
MariaDB > select * from students where age>=20 and age select * from students where age between 20 and 25;
练习：导入hellodb.sql，以下操作在students表上执行
1、以ClassID分组，显示每班的同学的人数；
MariaDB > select> 2、以Gender分组，显示其年龄之和；
MariaDB > select gender,sum(age) from students group by gender;
3、以ClassID分组，显示其平均年龄大于25的班级；
select> 4、以Gender分组，显示各组中年龄大于25的学员的年龄之和；
MariaDB > select gender,sum(age) from (select age,gender from students where age>25) as t group by gender;
练习：导入hellodb.sql，完成以下题目：
1、显示前5位同学的姓名、课程及成绩；
MariaDB > select name,course,score from (select * from students limit 5) as t,courses,scores where t.stuid=scores.stuid and scores.courseid=courses.courseid;
2、显示其成绩高于80的同学的名称及课程；
select name,course,score from students,(select * from scores where score > 80) as s,courses where students.stuid=s.stuid and s.courseid=courses.courseid;
3、求前8位同学每位同学自己两门课的平均成绩，并按降序排列；
select name,a from (select * from students limit 8) as s,(select stuid,avg(score) as a from scores group by stuid) as c where s.stuid=c.stuid order by a desc;
4、显示每门课程课程名称及学习了这门课的同学的个数；
select course,count(name) from (select name,course from students,courses,scores where students.stuid=scores.stuid and scores.courseid=courses.courseid) as a group by course;
select courses.course,count(stuid) from scores left join courses on scores.courseid=courses.courseid group by scores.courseid;
思考：
1、如何显示其年龄大于平均年龄的同学的名字？
MariaDB > select name from students where age > (select avg(age) from students);
2、如何显示其学习的课程为第1、2，4或第7门课的同学的名字？
MariaDB > select name from students,(select distinct stuid from (select * from scores where courseid in (1,2,4,7)) as a) as b where b.stuid=students.stuid;
select students.name from students,(select distinct stuid from scores where courseid in (1,2,4,7))as s where s.stuid=students.stuid;
3、如何显示其成员数最少为3个的班级的同学中年龄大于同班同学平均年龄的同学？
MariaDB > select student.name,student.age,student.classid,second.avg_age from (select students.name as name ,students.age as age,students.classid as> 4、统计各班级中年龄大于全校同学平均年龄的同学。
select name,age,classid from students where age > (select avg(age) as a from students);
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