精妙的SQL语句
求删除重复记录的sql语句？ 怎样把具有相同字段的纪录删除，只留下一条。例如，表test里有id,name字段
如果有name相同的记录 只留下一条，其余的删除。
name的内容不定，相同的记录数不定。
有没有这样的sql语句？
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A:一个完整的解决方案：
将重复的记录记入temp1表:
select [标志字段id],count(*) into temp1 from [表名]
group by [标志字段id]
having count(*)>1
2、将不重复的记录记入temp1表:
insert temp1 select [标志字段id],count(*) from [表名] group by [标志字段id] having count(*)=1
3、作一个包含所有不重复记录的表：
select * into temp2 from [表名] where 标志字段id in(select 标志字段id from temp1)
4、删除重复表:
delete [表名]
5、恢复表：
insert [表名] select * from temp2
6、删除临时表:
drop table temp1
drop table temp2
================================
B:
create table a_dist(id int,name varchar(20))
insert into a_dist values(1,'abc')
insert into a_dist values(1,'abc')
insert into a_dist values(1,'abc')
insert into a_dist values(1,'abc')
exec up_distinct 'a_dist','id'
select * from a_dist
create procedure up_distinct(@t_name varchar(30),@f_key varchar(30))
--f_key表示是分组字段﹐即主键字段
as
begin
declare @max integer,@id varchar(30) ,@sql varchar(7999) ,@type integer
select @sql = 'declare cur_rows cursor for select '+@f_key+' ,count(*) from ' +@t_name +' group by ' +@f_key +' having count(*) > 1'
exec(@sql)
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
select @type = xtype from syscolumns where> if @type=56
select @sql = 'delete from '+@t_name+' where ' + @f_key+' = '+ @id
if @type=167
select @sql = 'delete from '+@t_name+' where ' + @f_key+' = '+''''+ @id +''''
exec(@sql)
fetch cur_rows into @id,@max
end
close cur_rows
deallocate cur_rows
set rowcount 0
end
select * from systypes
select * from syscolumns where>
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