python urlparse模块的实用手册
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import urlparse
cve = 'CVE-2012-2143'
path = '/' + cve + '.html'
cveUrl = "http://cve.scap.org.cn/CVE-2015-2976.html" #URL
parsedUrl = urlparse.urlparse(cveUrl) #解构为tuple元组
print parsedUrl
urlList = list(parsedUrl) #元组转列表
urlList = path #修改列表
tup = tuple(urlList) #列表转元组
print urlList, tup
newUrl = urlparse.urlunparse(tup) #元组重构URL
print parsedUrl.geturl(), newUrl #geturl仅适用于urlparse()的结果，# urlunparse()可以重构普通列表为URL
C:\Python27\python.exe C:/Users/Administrator/PycharmProjects/excelTTT/TestUrllib.py
ParseResult(scheme='http', netloc='cve.scap.org.cn', path='/CVE-2015-2976.html', params='', query='', fragment='')
['http', 'cve.scap.org.cn', '/CVE-2012-2143.html', '', '', ''] ('http', 'cve.scap.org.cn', '/CVE-2012-2143.html', '', '', '')
http://cve.scap.org.cn/CVE-2015-2976.html http://cve.scap.org.cn/CVE-2012-2143.html
页:
[1]