perl 获取系统时间

scvmm

　　最近需要将字符串转换成时间，找了下资料，实战如下，发现时timelocal费了些时间
　　strftime也可在 c / c++ / awk / php 中使用，用法基本一致。
　　这个也不错
　　$time = strftime("%Y-%m-%d %H:%M:%S", localtime($time));
　　print "$time \n";
print str2time($time);



use POSIX qw(strftime);
use Time::Local;
use HTTP::Date;

my $time = "{\"date\":\"2013-06-24\",\"time\":\"01:53:40\"}";  
print "$time \n";
print str2time($time);
formattime($time);
sub formattime{
my ($srctime) = @_;
my ($year,$mon,$day,$hour,$min,$sec) = $srctime=~ /.+?(\d+)-(\d+)-(\d+).+?(\d+):(\d+):(\d+)/ ;
print "\n $year,$mon,$day,$hour,$min,$sec \n";
$time = str2time("$year-$mon-$day $hour:$min:$sec");
#print "$time \n";
#print strftime("%Y%m%d%H%M%S",localtime($time));
return $time;
}
　　



use strict;
use POSIX;
use Time::Local;

my $time = time();
print "$time \n";
my @time = localtime($time);
print "@time \n";
$time = strftime("%Y-%m-%d %H:%M:%S", localtime($time));
print "$time \n";
my ($year,$mon,$day,$hour,$min,$sec) = $time=~/(\d+)-(\d+)-(\d+) (\d+):(\d+):(\d+)/ ;
print "$year,$mon,$day,$hour,$min,$sec \n";
$time = timelocal($sec,$min,$hour,$day,$mon,$year);
print "$time \n";