设为首页 收藏本站
查看: 966|回复: 0

[经验分享] Oracle SQL语句生成日历(转)

[复制链接]

尚未签到

发表于 2016-8-10 06:42:22 | 显示全部楼层 |阅读模式
  1 要构造某年某月的日历,必须先知道这个月的开始时间,结束时间及天数
开始日期 例如 2006年11月
select to_date('20061101','yyyymmdd') as startDayOfMon from  dual;

结束日期
select last_day(to_date('20061101','yyyymmdd')) as endDayOfMon from  dual;

日期区间天数
select last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1 as DayOfMon
   from dual;

2 接下来就是需要得到开始时间到结束时间每一天的结果集
select * from (
select to_date('20061101','yyyymmdd') + level - 1 as everyDay from dual
   connect by level <=
   (last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1));

3 再进一步则是将该月中的日期分解成第几周,星期几。

select everyDay,to_char(everyday,'yyyy') as 年,
    to_char(everyday,'mm') as 月,
    to_char(everyday,'dd') as 日,
    to_char(everyday,'dy') as 星期几,
    lpad(to_char(everyday,'w'),6) as 该月的第几周,
    lpad(to_char(everyday,'ww'),6) as 该年的第几周
    from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay from dual
   connect by level <=
   (last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1));

4 这个结果集求出来后,接下拉就是使用DECODE函数进行行列转换了
select everyDay,to_char(everyday,'yyyy') as 年,
    to_char(everyday,'mm') as 月,
    to_char(everyday,'dd') as 日,
    to_char(everyday,'dy') as 星期几,
    lpad(to_char(everyday,'w'),6) as 该月的第几周,
    lpad(to_char(everyday,'ww'),6) as 该年的第几周,
    lpad(decode(to_char(everyday,'dy'),'星期日',to_char(everyday,'dd')),3) as 星期日,
    lpad(decode(to_char(everyday,'dy'),'星期一',to_char(everyday,'dd')),3) as 星期一,
    lpad(decode(to_char(everyday,'dy'),'星期二',to_char(everyday,'dd')),3) as 星期二,
    lpad(decode(to_char(everyday,'dy'),'星期三',to_char(everyday,'dd')),3) as 星期三,
    lpad(decode(to_char(everyday,'dy'),'星期四',to_char(everyday,'dd')),3) as 星期四,
    lpad(decode(to_char(everyday,'dy'),'星期五',to_char(everyday,'dd')),3) as 星期五,
    lpad(decode(to_char(everyday,'dy'),'星期六',to_char(everyday,'dd')),3) as 星期六
     from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay from dual
   connect by level <=
   (last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1));

5 再进一步就是统计汇总了,大家发现一个小问题没有?
   就是该月的第几周这里是按本月开始是星期几为开始的日期,很有意思,
   这样我们按该日是该年的第几周则是以今年开始日期是星期几为开始日期

select  to_char(everyday,'w') as week,
         sum(decode(to_char(everyday,'dy'),'星期日',to_char(everyday,'dd'))) as 星期日,
         sum(decode(to_char(everyday,'dy'),'星期一',to_char(everyday,'dd'))) as 星期一,
         sum(decode(to_char(everyday,'dy'),'星期二',to_char(everyday,'dd'))) as 星期二,
         sum(decode(to_char(everyday,'dy'),'星期三',to_char(everyday,'dd'))) as 星期三,
         sum(decode(to_char(everyday,'dy'),'星期四',to_char(everyday,'dd'))) as 星期四,
         sum(decode(to_char(everyday,'dy'),'星期五',to_char(everyday,'dd'))) as 星期五,
         sum(decode(to_char(everyday,'dy'),'星期六',to_char(everyday,'dd'))) as 星期六
     from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay
           from dual
           connect by level <= (last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1)
         )
   group by to_char(everyday,'w');

6 以上日历基本成功,但还有一个问题,就是一周的开始时间问题

select  to_char(everyday,'ww') as week,
         sum(decode(to_char(everyday,'dy'),'星期日',to_char(everyday,'dd'))) as 星期日,
         sum(decode(to_char(everyday,'dy'),'星期一',to_char(everyday,'dd'))) as 星期一,
         sum(decode(to_char(everyday,'dy'),'星期二',to_char(everyday,'dd'))) as 星期二,
         sum(decode(to_char(everyday,'dy'),'星期三',to_char(everyday,'dd'))) as 星期三,
         sum(decode(to_char(everyday,'dy'),'星期四',to_char(everyday,'dd'))) as 星期四,
         sum(decode(to_char(everyday,'dy'),'星期五',to_char(everyday,'dd'))) as 星期五,
         sum(decode(to_char(everyday,'dy'),'星期六',to_char(everyday,'dd'))) as 星期六
     from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay
           from dual
           connect by level <= (last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1)
         )
   group by to_char(everyday,'ww');

7  这样虽然可以解决,但还存在问题,大家可以考虑下!也可以考虑下年历怎么做!

select  ceil((to_char(everyday,'dd')+(to_char(to_date('20061101','yyyymmdd'),'d')-1))/7) as week,
         sum(decode(to_char(everyday,'dy'),'星期日',to_char(everyday,'dd'))) as 星期日,
         sum(decode(to_char(everyday,'dy'),'星期一',to_char(everyday,'dd'))) as 星期一,
         sum(decode(to_char(everyday,'dy'),'星期二',to_char(everyday,'dd'))) as 星期二,
         sum(decode(to_char(everyday,'dy'),'星期三',to_char(everyday,'dd'))) as 星期三,
         sum(decode(to_char(everyday,'dy'),'星期四',to_char(everyday,'dd'))) as 星期四,
         sum(decode(to_char(everyday,'dy'),'星期五',to_char(everyday,'dd'))) as 星期五,
         sum(decode(to_char(everyday,'dy'),'星期六',to_char(everyday,'dd'))) as 星期六
     from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay
           from dual
           connect by level <= (last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1)
         )
   group by ceil((to_char(everyday,'dd')+(to_char(to_date('20061101','yyyymmdd'),'d')-1))/7);

   以上是最终的结果。
  
  年日历
  select case
when (new_yweek = min(new_yweek)
over(partition by mon order by new_yweek)) then
mon_name
else
null
end as month,
new_yweek as yweek,
row_number() over(partition by mon order by new_yweek) as mweek,
sum(decode(wday, '1', mday, null)) as sun,
sum(decode(wday, '2', mday, null)) as mon,
sum(decode(wday, '3', mday, null)) as tue,
sum(decode(wday, '4', mday, null)) as wed,
sum(decode(wday, '5', mday, null)) as thu,
sum(decode(wday, '6', mday, null)) as fri,
sum(decode(wday, '7', mday, null)) as sat
from (select dayofyear as everyday,
to_char(dayofyear, 'mm') as mon,
to_char(dayofyear, 'Month') as mon_name,
to_char(dayofyear, 'w') as mweek,
to_char(dayofyear, 'ww') as yweek,
case
when (to_char(to_date(&year || '0101', 'yyyymmdd'), 'd') > '1') and
(to_char(dayofyear, 'd') <
to_char(to_date(&year || '0101', 'yyyymmdd'), 'd')) then
to_char(to_char(dayofyear, 'ww') + 1, 'fm00')
else
to_char(dayofyear, 'ww')
end as new_yweek,
to_char(dayofyear, 'd') as wday,
to_char(dayofyear, 'dd') as mday
from (select to_date(&year || '0101', 'yyyymmdd') + level - 1 as dayofyear
from dual
connect by level <=
to_char(to_date(&year || '1231', 'yyyymmdd'),
'ddd')))
group by mon, mon_name, new_yweek

运维网声明 1、欢迎大家加入本站运维交流群:群②:261659950 群⑤:202807635 群⑦870801961 群⑧679858003
2、本站所有主题由该帖子作者发表,该帖子作者与运维网享有帖子相关版权
3、所有作品的著作权均归原作者享有,请您和我们一样尊重他人的著作权等合法权益。如果您对作品感到满意,请购买正版
4、禁止制作、复制、发布和传播具有反动、淫秽、色情、暴力、凶杀等内容的信息,一经发现立即删除。若您因此触犯法律,一切后果自负,我们对此不承担任何责任
5、所有资源均系网友上传或者通过网络收集,我们仅提供一个展示、介绍、观摩学习的平台,我们不对其内容的准确性、可靠性、正当性、安全性、合法性等负责,亦不承担任何法律责任
6、所有作品仅供您个人学习、研究或欣赏,不得用于商业或者其他用途,否则,一切后果均由您自己承担,我们对此不承担任何法律责任
7、如涉及侵犯版权等问题,请您及时通知我们,我们将立即采取措施予以解决
8、联系人Email:admin@iyunv.com 网址:www.yunweiku.com

所有资源均系网友上传或者通过网络收集,我们仅提供一个展示、介绍、观摩学习的平台,我们不对其承担任何法律责任,如涉及侵犯版权等问题,请您及时通知我们,我们将立即处理,联系人Email:kefu@iyunv.com,QQ:1061981298 本贴地址:https://www.yunweiku.com/thread-255453-1-1.html 上篇帖子: Oracle查看所有表和字段 下篇帖子: 一些oracle关键词应用整理
您需要登录后才可以回帖 登录 | 立即注册

本版积分规则

扫码加入运维网微信交流群X

扫码加入运维网微信交流群

扫描二维码加入运维网微信交流群,最新一手资源尽在官方微信交流群!快快加入我们吧...

扫描微信二维码查看详情

客服E-mail:kefu@iyunv.com 客服QQ:1061981298


QQ群⑦:运维网交流群⑦ QQ群⑧:运维网交流群⑧ k8s群:运维网kubernetes交流群


提醒:禁止发布任何违反国家法律、法规的言论与图片等内容;本站内容均来自个人观点与网络等信息,非本站认同之观点.


本站大部分资源是网友从网上搜集分享而来,其版权均归原作者及其网站所有,我们尊重他人的合法权益,如有内容侵犯您的合法权益,请及时与我们联系进行核实删除!



合作伙伴: 青云cloud

快速回复 返回顶部 返回列表