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[经验分享] SQL to Mongo Mapping Chart

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发表于 2016-12-2 08:15:55 | 显示全部楼层 |阅读模式


SQL to Mongo Mapping Chart


  http://www.mongodb.org/display/DOCS/SQL+to+Mongo+Mapping+Chart

MySQL executable
Oracle executable
Mongo executable


mysqld



oracle



mongod





mysql



sqlplus



mongo






MySQL term
Mongo term/concept


database
database



table
collection



index
index



row
BSON
document


column
BSON field


join
embedding and linking



primary key
_id field



group by
aggregation



  MongoDB queries are expressed as JSON (BSON
) objects.  The following chart shows examples as both SQL and in  Mongo Query Language syntax. 
  The query expression in MongoDB (and other things, such as index key
patterns) is represented as JSON (BSON). However, the  actual verb
(e.g. "find") is done in one's regular programming  language; thus the
exact forms of these verbs vary by language.  The examples below are
Javascript and can be executed from the mongo shell
.

SQL Statement
Mongo Statement



CREATE TABLE USERS (a Number
, b Number
)





implicit; can also be done explicitly
with
db.createCollection("mycoll"
)








ALTER TABLE users ADD ...





implicit





INSERT INTO USERS VALUES(3,5)






db.users.insert({a:3,b:5})









SELECT a,b FROM users






db.users.find({}, {a:1,b:1})








SELECT * FROM users






db.users.find()








SELECT * FROM users WHERE age=33






db.users.find({age:33})








SELECT a,b FROM users WHERE age=33






db.users.find({age:33}, {a:1,b:1})








SELECT * FROM users WHERE age=33 ORDER BY name






db.users.find({age:33}).sort({name:1})








SELECT * FROM users WHERE age>33






db.users.find({age:{$gt:33}})








SELECT * FROM users WHERE age!=33






db.users.find({age:{$ne:33}})








SELECT * FROM users WHERE name LIKE "%Joe%"







db.users.find({name:/Joe/})








SELECT * FROM users WHERE name LIKE "Joe%"







db.users.find({name:/^Joe/})








SELECT * FROM users WHERE age>33 AND age<=40






db.users.find({'age':{$gt:33,$lte:40}})








SELECT * FROM users ORDER BY name DESC






db.users.find().sort({name:-1})








SELECT * FROM users WHERE a=1 and b='q'






db.users.find({a:1,b:'q'})








SELECT * FROM users LIMIT 10 SKIP 20






db.users.find().limit(10).skip(20)








SELECT * FROM users WHERE a=1 or b=2






db.users.find( { $or : [ { a : 1 } , { b : 2 } ] } )








SELECT * FROM users LIMIT 1






db.users.findOne()








SELECT order_id FROM orders o, order_line_items li WHERE li.order_id=o.order_id AND li.sku=12345






db.orders.find({"items.sku"
:12345},{_id:1})








SELECT customer.name FROM customers,orders WHERE orders.id="q179"
AND orders.custid=customer.id







var
o = db.orders.findOne({_id:"q179"
});
var
name = db.customers.findOne({_id:o.custid})










SELECT DISTINCT last_name FROM users






db.users.distinct('last_name')








SELECT COUNT(*y)
FROM users






db.users.count()








SELECT COUNT(*y)
FROM users where AGE > 30






db.users.find({age: {'$gt': 30}}).count()








SELECT COUNT(AGE) from users






db.users.find({age: {'$exists': true
}}).count()









CREATE INDEX myindexname ON users(name)







db.users.ensureIndex({name:1})








CREATE INDEX myindexname ON users(name,ts DESC)







db.users.ensureIndex({name:1,ts:-1})









EXPLAIN SELECT * FROM users WHERE z=3






db.users.find({z:3}).explain()









UPDATE users SET a=1 WHERE b='q'






db.users.update({b:'q'}, {$set:{a:1}}, false
, true
)








UPDATE users SET a=a+2 WHERE b='q'






db.users.update({b:'q'}, {$inc:{a:2}}, false
, true
)









DELETE FROM users WHERE z="abc"







db.users.remove({z:'abc'});







  More examples, specifically aggregation examples, here

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