def daemonize(stdout='/dev/null', stderr=None, stdin='/dev/null',
pidfile=None, startmsg = 'started with pid %s' ):
'''
This forks the current process into a daemon.
The stdin, stdout, and stderr arguments are file names that
will be opened and be used to replace the standard file descriptors
in sys.stdin, sys.stdout, and sys.stderr.
These arguments are optional and default to /dev/null.
Note that stderr is opened unbuffered, so
if it shares a file with stdout then interleaved output
may not appear in the order that you expect.
'''
# flush io
sys.stdout.flush()
sys.stderr.flush()
# Do first fork.
try:
pid = os.fork()
if pid > 0: sys.exit(0) # Exit first parent.
except OSError, e:
sys.stderr.write("fork #1 failed: (%d) %s\n" % (e.errno, e.strerror))
sys.exit(1)
# Decouple from parent environment.
os.chdir("/")
os.umask(0)
os.setsid()
# Do second fork.
try:
pid = os.fork()
if pid > 0: sys.exit(0) # Exit second parent.
except OSError, e:
sys.stderr.write("fork #2 failed: (%d) %s\n" % (e.errno, e.strerror))
sys.exit(1)
# Open file descriptors and print start message
if not stderr: stderr = stdout
si = file(stdin, 'r')
so = file(stdout, 'a+')
se = file(stderr, 'a+', 0) #unbuffered
pid = str(os.getpid())
sys.stderr.write("\n%s\n" % startmsg % pid)
sys.stderr.flush()
if pidfile: file(pidfile,'w+').write("%s\n" % pid)
# Redirect standard file descriptors.
os.dup2(si.fileno(), sys.stdin.fileno())
os.dup2(so.fileno(), sys.stdout.fileno())
os.dup2(se.fileno(), sys.stderr.fileno())
仔细比对前面说的步骤和代码,大体上是没有什么问题了,但是疑问就来了,os.fork()到底是怎么工作的呢,GOOGLE了个遍,最后的结论是这样:
父进程执行代码到os.fork()处时,会将自己整个拷贝一份(即子进程)这时候父进程os.fork()的返回值大于零(即子进程的PID),子进程os.fork()的返回值等于零,父进程结束,子进程继续执行,这时候又遇到第二个os.fork(),如上次一样,原来的子进程变成了父进程,又产生新的子进程,之后父进程就结束。这就能够说通第一次是避免process group leader,第二次是避免session group leader。子进程就变成了一个五终端,无会话的完全自我掌控的后台进程了。
欢迎大家讨论,不知道是否理解对了。