#通过迭代每组数据,调用sanitize函数,再把转换好的数据添加到新的列表中,这样列表中的数据风格就是一致的。
for each_t in james1:
clean_james.append(sanitize(each_t))
for each_t in julie1:
clean_julie.append(sanitize(each_t))
for each_t in mikey1:
clean_mikey.append(sanitize(each_t))
for each_t in sarah1:
clean_sarah.append(sanitize(each_t))
#!/usr/local/python3/bin/python3
def sanitize(time_string):
if '-' in time_string:
splitter='-'
elif ':' in time_string:
splitter=':'
else:
return(time_string)
(mins,secs) = time_string.split(splitter)
return(mins + '.' + secs)
#定义函数来解决去除重复数据项的问题,此函数接受两个列表作为参数带入,当数据不存在新列表中就把数据添加到新列表,如果有存在则不会添加,代替了下面使用每个列表使用for迭代的方式,代码更简洁。
def pomoto(old_list,new_list):
for i in old_list:
if i not in new_list:
new_list.append(i)
with open('james') as jam:
data = jam.readline()
james1 = data.strip().split(',')
with open('julie') as jul:
data = jul.readline()
julie1 = data.strip().split(',')
with open('mikey') as mik:
data = mik.readline()
mikey1 = data.strip().split(',')
with open('sarah') as sar:
data = sar.readline()
sarah1 = data.strip().split(',')
#从迭代的方式改为了列表推导的方式
clean_james = sorted([sanitize(each_t) for each_t in james1])
clean_julie = sorted([sanitize(each_t) for each_t in julie1])
clean_mikey = sorted([sanitize(each_t) for each_t in mikey1])
clean_sarah = sorted([sanitize(each_t) for each_t in sarah1])
#每列表迭代方式的去重复
#for i in clean_james:
# if i not in unique_james:
# unique_james.append(i)
#for i in clean_julie:
# if i not in unique_julie:
# unique_julie.append(i)
#for i in clean_mikey:
# if i not in unique_mikey:
# unique_mikey.append(i)
#for i in clean_sarah:
# if i not in unique_sarah:
# unique_sarah.append(i)
print(sorted(set([sanitize(i) for i in james1]),reverse=True)[0:3])
print(sorted(set([sanitize(i) for i in julie1]),reverse=True)[0:3])
print(sorted(set([sanitize(i) for i in mikey1]),reverse=True)[0:3])
print(sorted(set([sanitize(i) for i in sarah1]),reverse=True)[0:3])