python 使用pandas,完成对excel的操作： 遍历，求偏度（skew）的小程序

xinjiang

　　excel有针对偏度的计算函数 skew(), 但是不清楚怎么使用excel进行遍历， 数据量很大。
　　尝试使用python进行解决。
　　第一次学习python，没想到了在克服安装各种包的难过之后，居然成功实现了。
　　python3.3:



#this is a test case
# -*- coding: gbk -*-
print("hello python!中文")
#env config
import xlrd
import os
import xlwt3
import numpy
import pandas as pd
#from pandas import Series,DataFrame
#import pandas
data = xlrd.open_workbook("E:\\data.xlsx")
table = data.sheets()[0]   #this need to be verify more

#print ("check")
print (table.nrows)
print (table.name)
print ("############################")
#total line num
line_num=table.nrows
cell_sectionA=table.cell(1,0).value
cell_sectionB=table.cell(1,1).value
#print (cell_sectionA)
#print (cell_sectionB)
start_value=cell_sectionA
#we need to recode the start value ,but not the end.
sectionB_each_time_start=0
#sectionB_each_time_end=i is ok.
for i in range(1,line_num):
if start_value != table.cell(i,0).value:
cacu_num=i-sectionB_each_time_start;
#print (cacu_num)
#print ("********************************")
data={}
for j in range(0,(cacu_num-1)):
data[j]= table.cell((sectionB_each_time_start+j+1),1).value
#print (data[j])
df = pd.Series(data)
#print("skew\t")
#print("skew: %d  %f" %(table.cell(sectionB_each_time_start+1,0).value,df.skew()))
print("%d"%table.cell(sectionB_each_time_start+1,0).value)
#print("%f" %df.skew())
#after caculate ,update the variable.
sectionB_each_time_start=i-1
start_value=table.cell(i,0).value
#file=xlwt3.Workbook()
#table_for_wt=file.add_sheet("test1");

#table_for_wt.write(0,0,cell_b)
#table_for_wt.write(1,1,cell_b)
#file.save('E:\\wtest.xls')