perl函数指针

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　　看来的代码，测试通过



#!/usr/bin/perl
sub func1 {
print "func1 is running\n";
}
sub func_test {
my $func_ref = shift;
# ref will return 'CODE' if it's function reference
if ( ( ref($func_ref) eq "CODE" )
&& defined( &{$func_ref} ) )
{
&{$func_ref};
print $@ if $@;
}
else {
print "Not real function was called! \n";
}
}
## testing from here
my $func_ref = \&func1;
my $anoy_ref = sub { print "anonymous function is running\n" };
my $var      = "abcd";
my $var_ref  = \$var;
func_test($func_ref);
func_test($anoy_ref);
func_test($var);
func_test($var_ref)


my $variableName = 10 #定义私有变量


function test
{
my $a = shift;
}
#函数参数其实是个数组
#shift删除并返回数组第一个元素
　　修改之前的代码：



#! /usr/bin/perl
#传参测试
sub hello
{
my $a = shift;
print $a;
}
&hello("hello,world\n");
#返回值测试
sub max
{
my $a = shift;
my $b = shift;
if ($a > $b)
{
return $a;
}
else
{
return $b;
}
}
$n = &max(10,23);
print $n;
print "\n";