python模拟登录带windows安全窗口网站

流星城市

想使用python脚本来模拟登录，登录时需要输入windows安全窗口的用户名和密码。

我有用户名和密码，求解，如何通过python来模拟输入用户名和密码，并登录网站。

网站WEB.CONFIG中配置：

    <authorization>      <deny users="?"/>    </authorization>

1307077801

#!/usr/bin/python
#-*-coding:utf-8-*-

import urllib2

#登录的用户名和密码
username = "test"
password = "test"
url="http://192.168.209.200/"

def Func(url, username, password):
    try:
        # 创建一个密码管理者  
        password_mgr = urllib2.HTTPPasswordMgrWithDefaultRealm()  
        # 添加用户名和密码  
        password_mgr.add_password(None, url, username, password)  
        # 创建了一个新的handler  
        handler = urllib2.HTTPBasicAuthHandler(password_mgr)  
        # 创建 "opener"
        opener = urllib2.build_opener(handler)  
        # 使用 opener 获取一个URL  
        opener.open(url)  
        # 安装 opener.  
        urllib2.install_opener(opener)  
        #urllib2.urlopen 使用上面的opener.  
        ret = urllib2.urlopen(url)
        return ret.read()
    except urllib2.HTTPError, e:
        if e.code == 401:
           return "authorization failed"
        else:
            raise e
    except:
        return None

print Func(url, username, password)

流星城市

1307077801 发表于 2016-2-29 10:55
#!/usr/bin/python
#-*-coding:utf-8-*-

我改了用户名、密码和URL，发现还有问题，报错信息如下：
（注：windows安全是域账号，会不会是这个问题有影响？我在用户名前加和没加 域名\test都报同样错误）

E:\py>python pyweb_sps2.py
Traceback (most recent call last):
  File "pyweb_sps2.py", line 36, in <module>
    print Func(url, username, password)
  File "pyweb_sps2.py", line 21, in Func
    opener.open(url)
  File "C:\Python27\lib\urllib2.py", line 437, in open
    response = meth(req, response)
  File "C:\Python27\lib\urllib2.py", line 550, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Python27\lib\urllib2.py", line 475, in error
    return self._call_chain(*args)
  File "C:\Python27\lib\urllib2.py", line 409, in _call_chain
    result = func(*args)
  File "C:\Python27\lib\urllib2.py", line 558, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 401: Unauthorized

1307077801

域的没测试过，报错是： HTTP Error 401: Unauthorized
应该是验证没通过

你看一下urllib2的文档吧，应该有办法可以解决的。

流星城市

1307077801 发表于 2016-2-29 11:43
域的没测试过，报错是： HTTP Error 401: Unauthorized
应该是验证没通过

网上看到一篇文章（地址：http://code.activestate.com/recipes/305288/），报错内容是
The authentication line is badly formed
请问有没有办法解决？





import urllib2, sys, re, base64from urlparse import urlparsetheurl = 'http://www.someserver.com/somepath/somepage.html'            # if you want to run this example you'll need to supply a protected page with your username and passwordusername = 'johnny'password = 'XXXXXX'            # a very bad passwordreq = urllib2.Request(theurl)try:    handle = urllib2.urlopen(req)except IOError, e:                  # here we are assuming we fail    passelse:                               # If we don't fail then the page isn't protected    print "This page isn't protected by authentication."    sys.exit(1)    if not hasattr(e, 'code') or e.code != 401:                 # we got an error - but not a 401 error    print "This page isn't protected by authentication."    print 'But we failed for another reason.'    sys.exit(1)authline = e.headers.get('www-authenticate', '')                # this gets the www-authenticat line from the headers - which has the authentication scheme and realm in itif not authline:    print 'A 401 error without an authentication response header - very weird.'    sys.exit(1)    authobj = re.compile(r'''(?:\s*www-authenticate\s*:)?\s*(\w*)\s+realm=['"](\w+)['"]''', re.IGNORECASE)          # this regular expression is used to extract scheme and realmmatchobj = authobj.match(authline)if not matchobj:                                        # if the authline isn't matched by the regular expression then something is wrong    print 'The authentication line is badly formed.'    sys.exit(1)scheme = matchobj.group(1) realm = matchobj.group(2)if scheme.lower() != 'basic':    print 'This example only works with BASIC authentication.'    sys.exit(1)base64string = base64.encodestring('%s:%s' % (username, password))[:-1]authheader =  "Basic %s" % base64stringreq.add_header("Authorization", authheader)try:    handle = urllib2.urlopen(req)except IOError, e:                  # here we shouldn't fail if the username/password is right    print "It looks like the username or password is wrong."    sys.exit(1)thepage = handle.read()    server = urlparse(theurl)[1].lower()            # server names are case insensitive, so we will convert to lower casetest = server.find(':')if test != -1: server = server[:test]           # remove the :port information if present, we're working on the principle that realm names per server are likely to be unique...passdict = {(server, realm) : authheader }      # now if we get another 401 we can test for an entry in passdict before having to ask the user for a username/passwordprint 'Done successfully - information now stored in passdict.'print 'The webpage is stored in thepage.'

1307077801

建议有环境还是改代码来调试吧。直接套代码不一定通用的。

qq258444257

流星城市 发表于 2016-2-29 14:13
网上看到一篇文章（地址：http://code.activestate.com/recipes/305288/），报错内容是
The authenticat ...

请问问题解决了吗？