使用python发送html的邮件

meimei10251314 · 发表于 2017-5-3 08:03:13

实现功能1：查询数据，然后做成报表，再发送这些报表
　　代码：

写道

import smtplib
from datetime import datetime, timedelta
import time
from email.MIMEText import MIMEText
from email.MIMEMultipart import MIMEMultipart

def get_html_msg(send_date):
head = """<head><meta charset="utf-8">
<STYLE TYPE="text/css" MEDIA=screen>

</STYLE>
</head>"""

p = """<p>大家好：<br>截止到 """ + get_cpu_report_date(send_date, format_min) + """,各个设备性能指标报表如下，请查阅。<br></p>"""

body = """<body>""" + p + """
<table border="0" cellpadding="0" cellspacing="0">
<th>""" + get_cpu_table() +"""</th>
<th>"""+get_io_table() + """</th>
<th>"""+get_load_table() + """</th>
<th>"""+get_memory_table() + """</th>
<th>"""+get_process_speed_table() + """</th>
</table>
</body>"""
html = """<html>""" + head + body + """</html>"""
return html

def send_mail(html_msg):
msg = MIMEMultipart()
content = MIMEText(html_msg,'html')
msg.attach(content)
msg['To'] = ";".join(to_list)
msg['From'] = from_addr
msg['Subject'] = subject
s = smtplib.SMTP('xxxx')
s.set_debuglevel(0)
s.sendmail(from_addr, to_list, msg.as_string())
s.quit()
print "ok"

if __name__ == "__main__":
now = datetime.now()
html = get_html_msg()
send_mail(html)
　　实现功能2(发送附件）：（转载）

#!/usr/bin/env python
#-*-coding:utf8-*-
import os, smtplib, mimetypes
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
MAIL_LIST = ["username@iyunv.com"]
MAIL_HOST = "smtp.iyunv.com"
MAIL_USER = "username"
MAIL_PASS = "password"
MAIL_POSTFIX = "iyunv.com"
MAIL_FROM = MAIL_USER + "<"+MAIL_USER + "@" + MAIL_POSTFIX + ">"
def send_mail(subject, content, filename = None):
try:
message = MIMEMultipart()
message.attach(MIMEText(content))
message["Subject"] = subject
message["From"] = MAIL_FROM
message["To"] = ";".join(MAIL_LIST)
if filename != None and os.path.exists(filename):
ctype, encoding = mimetypes.guess_type(filename)
if ctype is None or encoding is not None:
ctype = "application/octet-stream"
maintype, subtype = ctype.split("/", 1)
attachment = MIMEImage((lambda f: (f.read(), f.close()))(open(filename, "rb"))[0], _subtype = subtype)
attachment.add_header("Content-Disposition", "attachment", filename = filename)
message.attach(attachment)
smtp = smtplib.SMTP()
smtp.connect(MAIL_HOST)
smtp.login(MAIL_USER, MAIL_PASS)
smtp.sendmail(MAIL_FROM, MAIL_LIST, message.as_string())
smtp.quit()
return True
except Exception, errmsg:
print "Send mail failed to: %s" % errmsg
return False
if __name__ == "__main__":
if send_mail("测试信", "我的博客欢迎您/", r"G:\attachment.rar"):
print "发送成功！"
else:
print "发送失败！"

1、首先要理解一个常识(RFC)
RFC(The Request for Comments)是一个关于Internet各种标准的文档，定义了很多的网络协议和数据格式，标准的Internet邮件遵从RFC2822(Internet Message Format)等几个文档，其中RFC822中描述了邮件头(mail headers)的格式。具体文档在Python帮助里都可以查到全文。
2、其次要熟悉Python的几个模块
关于邮件的有email，smtplib等，关于编码的有base64，binascii等，发送邮件的方式就是先根据RFC构造好邮件的各个部分，然后登录到smtp服务器sendmail就可以了。
3、下面贴代码
1

# -*- coding: cp936 -*-
2
3from email.Header import Header
4from email.MIMEText import MIMEText
5from email.MIMEMultipart import MIMEMultipart
6import smtplib, datetime
7
8#创建一个带附件的实例
9msg = MIMEMultipart()
10
11#构造附件
12att = MIMEText(open('d:\\tc201.rar', 'rb').read(), 'base64', 'gb2312')
13att["Content-Type"] = 'application/octet-stream'
14att["Content-Disposition"] = 'attachment; filename="tc201.rar"'
15msg.attach(att)
16
17#加邮件头
18msg['to'] = 'zhousl@xxx.com'
19msg['from'] = 'zhousl@xxx.com'
20msg['subject'] = Header('冒烟测试结果 (' + str(datetime.date.today()) + ')', \
21 'gb2312')
22#发送邮件
23server = smtplib.SMTP('smtp.xxx.com')
24server.sendmail(msg['from'], msg['to'], \
25 msg.as_string())
26server.close
4、几个值得注意的地方
1)构造附件时注意采用正确的字符集，这个困惑我好久，开始没有用gb2312，发过去的压缩文件就是坏的；
2)上面的代码中没有包括登录smtp服务器的指令，而Internet上面的smtp服务器一般都是要求认证的，可以通过smtp.login方法进行登陆
3)sendmail方法中的参数to可以是包含多个地址的元组，这样可以发送邮件给多个人了
4)Python2.4以前的版本是不支持gb2312字符集的，要下载安装Python2.4才能跑上面的代码，当然2.4.1肯定会更好一点

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[经验分享] 使用python发送html的邮件

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