清除svn信息文件的python代码

yanfangsheng123

写了一个简单的脚本来清除.svn文件夹。从svn代码仓库得到的源代码，在每一个目录及了目录下都有一个名为.svn文件夹。当想将svn下载的代码导入到其它project中时，就需要将svn相关信息文件删除掉，得到一份干净的代码。
如下注事点：
1.遍历目录及子目录，如果发现有名为.svn的文件夹，就将它删除。os.path.walk()来遍历目录，os.remove(path)删除文件，os.rmdir(path)删除文件夹。
2. 在删除文件之前，需要去掉只读属性：os.chmod(path, st_mode | stat.S_IWRITE | stat.S_IWGRP | stat.S_IWOTH)


# script to clean .svn folder
import os, os.path
import stat
BASE_FOLDER = r'C:\Development\workspace-3.6\ESI_back'
class Walker():
def __init__(self, begin_path, rm_name):
self.begin_path = begin_path
self.rm_name = rm_name
def going(self):
os.path.walk(self.begin_path, self.visit, self.rm_name)
def visit(self, arg, dirname, names):
#if os.path.isabs(dirname):
#print 'absolute pathname: ', dirname
for e in names:
abs = os.path.join(dirname, e)
if e == arg and os.path.isdir(abs):
#print "Removing: ", abs
self.rm_force(abs)
#print "done"
def rm_force(self, path):
if os.path.lexists(path):
#if path is readonly, should remove "readonly"
self.un_readonly(path)
if os.path.isfile(path):
print 'Removing file: ', path
os.remove(path)
elif os.path.isdir(path):
names = os.listdir(path)
for name in names:
abs = os.path.join(path, name)
self.rm_force(abs)
print 'Removing folder: ', path
os.rmdir(path)
else:
os.unlink(path)
else:
print 'NOT EXISTS: ', path
def is_readonly(self, path):
st_mode = os.stat(path).st_mode
#return st_mode == 33060
return st_mode & stat.S_IWRITE != stat.S_IWRITE
def un_readonly(self, path):
st_mode = os.stat(path).st_mode
os.chmod(path, st_mode | stat.S_IWRITE | stat.S_IWGRP | stat.S_IWOTH) #146
#os.chmod(path, 33206)

if __name__ == '__main__':
if not os.path.isdir(BASE_FOLDER):
print 'Not a folder: ', BASE_FOLDER
exit
walker = Walker(BASE_FOLDER, '.svn')
#f = r't/t.txt'
#print walker.is_readonly(f)
#walker.un_readonly(f)
#print walker.is_readonly(f)
#walker.rm_force('C:\\TEMP\\zhouvi2')
walker.going()