python ElementTree解析xml小记

jrgf

　　学python没多久,遇到一个解析xml的需求，边学边练，用的是ElementTree，感觉没有说的那么方便，也许E文不好，看漏api,root.findall()搞的象正则表达式，瞎了。希望知道的朋友告诉我
　　题目这样，比如有个xml：

<?xml version="1.0" encoding="UTF-8"?>
<students>
<student no="2009081097">
<name>Hongten</name>
<gender>M</gender>
<age>20</age>
<score subject="math">97</score>
<score subject="chinese">90</score>
</student>
<student no="2009081098">
<name>DuDu</name>
<gender>W</gender>
<age>21</age>
<score subject="math">87</score>
<score subject="chinese">96</score>
</student>
<student no="2009081099">
<name>Sum</name>
<gender>M</gender>
<age>19</age>
<score subject="math">64</score>
<score subject="chinese">98</score>
</student>
</students>
　　已知某个值是19，求拥有该值的节点的父节点的所有子节点，就是这么一块：

        <name>Sum</name>
<gender>M</gender>
<age>19</age>
<score subject="math">64</score>
<score subject="chinese">98</score>
　　我的代码：

#coding=utf-8
import os
import xml.etree.ElementTree as ET
filepath = 'c:\\test\\a.xml'
tree = ET.parse(filepath)
root = tree.getroot()
p_node = None
r_node = []
def func(node):
global p_node
if len(node)>0:
p_node = node
for c in node:
func(c)
else:
if node.text == '19':#值在这里在这里
r_node.append(p_node)
if __name__ == '__main__':
func(root)
if not r_node:
for n in r_node:
print '-'*10
for c in n:
print c.tag,c.text
else:
print 'not found'

　　输出：

----------
name Sum
gender M
age 19
score 64
score 98
[Finished in 0.1s]
　　先这样吧，交差！