python 如何得到匹配到string的行

ty9919

　　文件名:change.log
我想匹配到error并返回行.

类似于grep error change.log

用python如何实现？




change.log 文件内容

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用perl实现如下：
#!/usr/bin/perl -w

open(F1,"change.log"||die "Cannot open change.log!";

my @grp=<F1>;

foreach my $va(@grp) {
        #print $va;

if ($va=~/error/i) {

        print "$va\n";
}
}


python怎么匹配？
　　1.
　　print ''.join([x for x in open('change.log').readlines() if x.find('error')!=-1])
　　2.
　　print (''.join([x for x in open('change.log').readlines() if re.search('error',x)]))
　　3.忽略大小写
　　转换成小写或大写来判断就等于忽略大小写了
　　print( "".join([x for x in open('change.log').readlines() if x.lower().find('error')!=-1]))
　　print( "".join([x for x in open('change.log').readlines() if x.upper().find('ERROR')!=-1]))
　　正则
　　print (''.join([x for x in open('change.log').readlines() if re.search('error',x,re.I)]))
　　1.
　　#!/usr/bin/python
　　a=open("change.log").readlines()
　　for x in a:
 if x.find("error") != -1:
  print(x)
　　2.
　　#!/usr/bin/python
import re
　　a=open("change.log").readlines()
#print(a)
　　for x in a:
 #print(x)
 if re.search("error",x,re.I):
  print(x,end="")
　　http://bbs.chinaunix.net/thread-3729007-1-1.html