shell 脚本 ,看不懂啊 谁能帮忙解释下这个脚本

i1zhuxian

脚本内容如下:

[Shell] 纯文本查看 复制代码

#!/bin/bash
SUDO_BINARY="/usr/bin/sudo"

if [[ $# -eq 0 ]] ; then
  echo 'usage: ambari-sudo.sh [sudo_arg1, sudo_arg2 ...] command [arg1, arg2 ...]'
  exit 1
fi

# if user is non-root
if [ "$EUID" -ne 0 ] ; then
  $SUDO_BINARY "$@"
else
  ENV=()
  SUDO_ARGS=()

  for i ; do
    if [[ "$i" == *"="* ]] ; then
      ENV+=("$i")
      shift
    elif [[ "$i" == "-"* ]] ; then
      SUDO_ARGS+=("$i")
      shift
    else
      break
    fi
  done
  
  echo "sudo arguments: ${SUDO_ARGS[@]}"
  echo "env: ${ENV[@]}"
  echo "args: $@"

  if [ "$ENV" ] ; then
    export "${ENV[@]}"
  fi

  "$@"
fi

特别是for i ; do 这块,不应该是for i in xx ; od 么
执行了 下这个脚本发现是没问题的.

[Shell] 纯文本查看 复制代码

[iyunv@hadoop2 scripts]# /var/lib/ambari-agent/ambari-sudo.sh  -H -E /usr/ADH/hadoop/sbin/hadoop-daemon.sh --config /etc/hadoop/conf start secondarynamenode
sudo arguments: -H -E
env: 
args: /usr/ADH/hadoop/sbin/hadoop-daemon.sh --config /etc/hadoop/conf start secondarynamenode
starting secondarynamenode, logging to /usr/ADH/hadoop/logs/root/hadoop-root-secondarynamenode-hadoop2.com.out

知呼

i1zhuxian

for i :do
可以看作是 for i in "$@"的简写