ZOJ1058Currency Exchange

luobo2ni

　　Time Limit: 1 Second      Memory Limit: 32768 KB
　　When Issac Bernand Miller takes a trip to another country, say to France, he exchanges his US dollars for French francs. The exchange rate is a real number such that when multiplied by the number of dollars gives the number of francs. For example, if the exchange rate for US dollars to French francs is 4.81724, then 10 dollars is exchanged for 48.1724 francs. Of course, you can only get hundredth of a franc, so the actual amount you get is rounded to the nearest hundredth. (We'll round .005 up to .01.) All exchanges of money between any two countries are rounded to the nearest hundredth.
　　Sometimes Issac's trips take him to many countries and he exchanges money from one foreign country for that of another. When he finally arrives back home, he exchanges his money back for US dollars. This has got Issac thinking about how much if his unspent US dollars is lost (or gained!) to these exchange rartes. You'll compute how much money Issac ends up with if he exchanges it many times. You'll always start with US dollars and you'll always end with US dollars.
　　Input
　　The first 5 lines of input will be the exchange rates between 5 countries, numbered 1 through 5. Line i will five the exchange rate from country i to each of the 5 countries. Thus the jth entry of line i will give the exchange rate from the currency of country i to the currency of country j. the exchange rate form country i to itself will always be 1 and country 1 will be the US. Each of the next lines will indicate a trip and be of the form
　　N c1 c2 �� cn m
　　Where 1 <= n <= 10 and c1, ��, cn are integers from 2 through 5 indicating the order in which Issac visits the countries. (A value of n = 0 indicates end of input, in which case there will be no more numbers on the line.) So, his trip will be 1 -> c1 -> c2 -> �� -> cn -> 1. the real number m will be the amount of US dollars at the start of the trip.
　　Output
　　Each trip will generate one line of output giving the amount of US dollars upon his return home from the trip. The amount should be fiven to the nearest cent, and should be displayed in the usual form with cents given to the right of the decimal point, as shown in the sample output. If the amount is less than one dollar, the output should have a zero in the dollars place.
　　This problem contains multiple test cases!
　　The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.
　　The output format consists of N output blocks. There is a blank line between output blocks.
　　
Sample Input
　　1
　　1 1.57556 1.10521 0.691426 7.25005
0.634602 1 0.701196 0.43856 4.59847
0.904750 1.42647 1 0.625627 6.55957
1.44616 2.28059 1.59840 1 10.4843
0.137931 0.217555 0.152449 0.0953772 1
3 2 4 5 20.00
1 3 100.00
6 2 3 4 2 4 3 120.03
0
　　Sample Output
　　19.98
99.99
120.01
　　
　　再加组测试数据吧：
　　2
　　1 1.57556 1.10521 0.691426 7.25005
0.634602 1 0.701196 0.43856 4.59847
0.904750 1.42647 1 0.625627 6.55957
1.44616 2.28059 1.59840 1 10.4843
0.137931 0.217555 0.152449 0.0953772 1
3 2 4 5 20.00
1 3 100.00
6 2 3 4 2 4 3 120.03

问题有：
　　1.输出结果要进行四舍五入！！！
　　2.输出格式注意，被PE到oj上前五个全是我的id
　　Code:
　　#include<stdio.h>//考虑什么的四舍五入？？？
int main()
{
int N,n,c[10],k;//N表示测试的组数，n为经过的国家的数
double a[6][6],total=0;
scanf("%d",&N);
while(N--)
{
  for(int i=1;i<6;i++)
   for(int j=1;j<6;j++)
    scanf("%lf",&a[j]);
   while(scanf("%d",&n)!=EOF&&n)
   {
    for(k=1;k<=n;k++)
     scanf("%d",&c[k]);
    c[0]=c[n+1]=1;//两级设1，从1出发又回到1!!!
    scanf("%lf",&total);
    for(k=0;k<n+1;k++)
    {
     total=total*a[c[k]][c[k+1]];
     total=(int)(total*100+0.5);//这便是四舍五入操作！！！
     total=(double)total/100;  
     
    }
    printf("%.2lf/n",total);
   
   
   }if(N)printf("/n");//这里被PE了n次，纠结的是输出每组测试组数之间要有空行，碰到这么多题还在这里出错！！！
}
return 0;
}