perl学习(9) 实例：取出操作时间最长的100个记录

爱若晨风

　　需求描述：
　　日志记录了一次操作的时间,即server端接收包到发送结果到client端的时间，取出操作时间最长的100个记录。
　　
　　日志信息片段：
　　[2013-09-13 15:23:50,445.500] [47028700024080] FATAL - socket = 9
[2013-09-13 15:23:50,446.156] [47028700024080] FATAL - a client connected with ip: 10.10.10.127, name: <unknown>, port: 2314
[2013-09-13 15:23:50,447.375] [1103333696] INFO  - recv: with 64 bytes from 10.10.10.127.
[2013-09-13 15:23:50,449.461] [1103333696] INFO  - send: 1 with 1 bytes.
　　.........
　　[iyunv@sjs_131_126 analyse_time]# cat sort.sh

#!/bin/sh
#cat $1 | perl split.pl
grep -n 'FATAL - socket\|INFO  - send:' $1 |awk -F']' '{print $1 $3}'|awk -F'[' '{print  $1 "\t"t$2}'> result1.txt
echo "result1 success!"
./analyze.pl result1.txt
echo "result2 success!"
#
cat result2.txt | sort -t: -r | head -100 >result.txt
echo "success!"
　　说明：
　　1.第一步，将开始和结束的日志提取到result1.txt
　　2.第二步，通过analyze.pl计算每次操作的时间写入result2.txt
　　3.第三步，排序取出前100条
　　
[iyunv@sjs_131_126 analyse_time]# cat analyze.pl

#!/usr/bin/perl -w
use strict;
use warnings ;
use Time::Local;
open FD1, ">> result_error.txt" ;
open FD2, ">> result2.txt";
my $need_end = 0;
my ($second, $minute, $hour, $date, $month, $year);
my $begin = 0;
my $end = 0;
my $begin_time = 0;
my $end_time = 0;
#sample
#6653:   2013-09-11 15:04:35,815.499 FATAL - socket = 8
#6656:   2013-09-11 15:04:35,821.075 INFO  - send: 1 with 1 bytes.
while(<>)
{
chomp ;
if($need_end == 0)
{
if(/(\d+):\t(\d+)-(\d+)-(\d+)\s(\d+):(\d+):(\d+),.*\s(INFO|FATAL).*/s)
{
if($8 eq "FATAL")
{
$begin = $1;
$need_end = 1;
($second, $minute, $hour, $date, $month, $year) = ($7, $6, $5, $4, $3 - 1, $2 - 1900);
$begin_time = timelocal($second, $minute, $hour, $date, $month, $year);
#print "$year-$month-$date $hour:$minute:$second\n"
}
else
{
print FD1  "$_\n" ;
$need_end = 0 ;
}
}
else
{
die  "match error\n" ;
}
}
elsif($need_end == 1)
{
if(/(\d+):\t(\d+)-(\d+)-(\d+)\s(\d+):(\d+):(\d+),.*\s(INFO|FATAL).*/s)
{
$end = $1;
if( $end == $begin + 3 && $8 eq "INFO")
{
$end = $1;
$need_end = 0;
($second, $minute, $hour, $date, $month, $year) = ($7, $6, $5, $4, $3 - 1, $2 - 1900);
$end_time = timelocal($second, $minute, $hour, $date, $month, $year);
my $duration = $end_time - $begin_time;
print FD2 "$duration:[$begin to $end]\n";
}
else
{
$need_end = 0 ;  
print FD1  "$_\n" ;
}
}
}
else
{
die  "control error\n" ;
}
}