Shell脚本之IP网络地址和广播地址计算

21ewd

这是一篇旧时习作，Shell脚本练得多了，想练练移位计算，就有了下面的脚本。

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#!/bin/bash IPPattern="(\<([0-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])\>\.){3}\<([0-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])\>" maskPattern="[1-9]|[12][0-9]|3[01]" while : do   echo -e -n "Please input a legal IP address [such as 192.168.1.1/16]: "   read userInput   IPMask=`echo $userInput | egrep "$IPPattern/$maskPattern"`     #Such as 192.168.1.1/24   if [ -z "$IPMask" ] ;then     echo "Please input the right format. [such as 192.168.1.1/1-31] "     continue   fi   IPAddr=`echo $IPMask | cut -d/ -f1`   IPType[1]=`echo $IPAddr | cut -d. -f1`   IPType[2]=`echo $IPAddr | cut -d. -f2`   IPType[3]=`echo $IPAddr | cut -d. -f3`   IPType[4]=`echo $IPAddr | cut -d. -f4`   mask=`echo $IPMask | cut -d/ -f2`   echo "IP address is ${IPType[1]}*${IPType[2]}*${IPType[3]}*${IPType[4]} , Mask is $mask ."   ((IPHex[1]=IPType[1]<<24))   ((IPHex[2]=IPType[2]<<16))   ((IPHex[3]=IPType[3]<<8))   ((IPHex[4]=IPType[4]))   #192 c0 ; 1 1 1   ((iph=${IPHex[1]}+${IPHex[2]}+${IPHex[3]}+${IPHex[4]}))   #echo $iph   #0xffffffff   #declare -i strMask1=4294967295   declare -i strMask1=0xffffffff   #echo $strMask1   ((strMask1=strMask1<<(32-mask) & 0xffffffff))   #echo $strMask1   ((strMask2=~strMask1))   #echo $strMask2   ((networkAddr=iph & strMask1))   ((bcastAddr= (iph | strMask2) &  0xffffffff))   #echo $networkAddr | awk '{printf "%x\n",$0}'   #echo $bcastAddr | awk '{printf "%x\n",$0}'   ((IPHex[1]=networkAddr>>24 & 0x000000ff))   ((IPHex[2]=networkAddr>>16 & 0x000000ff))   ((IPHex[3]=networkAddr>>8 & 0x000000ff))   ((IPHex[4]=networkAddr & 0x000000ff))   echo -e "Network Address   : ${IPHex[1]}.${IPHex[2]}.${IPHex[3]}.${IPHex[4]}"   ((IPHex[1]=bcastAddr>>24 & 0x000000ff))   ((IPHex[2]=bcastAddr>>16 & 0x000000ff))   ((IPHex[3]=bcastAddr>>8 & 0x000000ff))   ((IPHex[4]=bcastAddr & 0x000000ff))   echo -e "Broadcast Address : ${IPHex[1]}.${IPHex[2]}.${IPHex[3]}.${IPHex[4]}" done