python 元组tuple

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# -*- coding: utf8 -*- """ 元组的相关测试, 基本和列表一模一样,除了元素不能被修改,元组用小括号括起,实际起作用的是逗号 """ #定义 #空元组 tuple1 = () #创建一个元素,和列表有所区别 tupleOne1 = ('hello',) tupleOne2 = 'hello', #小括号可以不加,但最好加上 tupleOne3 = tuple(('hello',)) print(tupleOne1)  #('hello',) print(tupleOne2)  #('hello',) print(tupleOne3)  #('hello',) #创建方式 tuple2 = ('a', 2.2, (1, 'b'), {'pi': 3.14}, 3e-2) print(tuple2)  #('a', 2.2, (1, 'b'), {'pi': 3.14}, 0.03) strTemp = 'hello' tuple3 = tuple(strTemp) print(tuple3)  #('h', 'e', 'l', 'l', 'o') tuple333 = tuple(('hello',)) #注意传入的是一个元组,此处可简写成tuple333 = ('hello',) print(tuple333)  #('h', 'e', 'l', 'l', 'o') strTemp = 'worlld' print(tuple3) list1 = [1, 'a', 3.3] tuple4 = tuple(list1) print(tuple4)  #(1, 'a', 3.3) #修改元组元素,只能通过拼接的方法'修改' #tuple4[1] = 'b'  #肯定报错:TypeError: 'tuple' object does not support item assignment(元组不支持里面的项被改变) tuple4 = tuple4[:1] + ('new',) + tuple4[1:]  #注意要加逗号(1, 'new', 'a', 3.3) print(tuple4)  #(1, 'a', 3.3) #直接赋值不会创建新内存,只是等于这块内存多了一个标签 tuple5 = tuple2 print('t5=%d, t2=%d' % (id(tuple5), id(tuple2))) print(tuple5)  #('a', 2.2, (1, 'b'), {'pi': 3.14}, 0.03) tuple2 = tuple2[:1] + tuple2[2] print(tuple2)  #('a', 1, 'b') print(tuple5)  #('a', 2.2, (1, 'b'), {'pi': 3.14}, 0.03) #长度 tuple6 = (1, 3, 4) print(len(tuple6))  #3 #查找某一个元素的个数 print(tuple6.count(3)) #1 个数1个 #查找该元素第一次出现的位置索引 print(tuple6.index(4)) #2 ,索引为2 print(tuple6.index(4,0,3)) #2 ,索引为2, 索引区间[0, 3),不包含3 print(tuple6.index(4,1)) #2 ,索引为2, 索引区间[1, 3),不包含3 #print(tuple6.index(4, 0, 2))  #报异常,搜不到这个值在该区间内  ValueError: tuple.index(x): x not in tuple #元组的比较 print(max(tuple6))  #4 tuple66 = ('a', 2.2, (1, 'b'), {'pi': 3.14}, 0.03) print(max(tuple66))  #(1, 'b')  暂时不知道为什么 tuple7 = ('a','b','c') tuple8 = ('e', 'f', 'g') print(min(tuple7))  #a print(cmp(tuple7, tuple8))  #-1, 即tuple7<tuple8 (注:0相等,1大于) #删除元素,只能通过拼接的方法'删除' tuple6 = (1, 2, 3, 4) #del(tuple6[1])  #肯定报错,不能修改内部元素,TypeError: 'tuple' object doesn't support item deletion tuple6 = tuple6[:1] + tuple6[2:] print(tuple6)  #(1, 3, 4) #清空 del(tuple6) tuple7 = [1, 2, 3.4, 4, 5, 6] print(max(tuple7))  #6 print(min(tuple7))  #1 print(tuple7[2])  #3.4 print(tuple7[-2])  #5 加个负号就相当于从后往前查找 tuple7[-n] == tuple7[len(li) - n] print(tuple7[-0])  #1  相当于list12[0],