Sql Server按树形结构排序查询表记录（CSDN论坛转载）

xingyu655

WITH T AS
(
SELECT CAST(Tree_Id AS VARCHAR(20)) AS CODE,*,CAST(City_Id AS VARBINARY(MAX)) AS px  FROM Class_City AS A
WHERE NOT EXISTS(SELECT * FROM Class_City WHERE City_Id=A.Father_Id)
UNION ALL
SELECT CAST(B.Tree_Id+A.Tree_Id AS VARCHAR(20)),A.*,CAST(B.px+CAST(A.City_Id AS VARBINARY) AS VARBINARY(MAX))  FROM Class_City AS A
JOIN T AS B ON A.Father_Id=B.City_Id
)
SELECT City_Id,HelpCode,City_Name,Class_Class,Father_Id FROM T
ORDER BY px
　　以下是论坛中的代码：
　　

　　

--------------------------------------------------------------------------
--  Author : htl258(Tony)
--  Date   : 2010-04-23 02:37:28
--  Version:Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86)
--          Jul  9 2008 14:43:34
--          Copyright (c) 1988-2008 Microsoft Corporation
--          Developer Edition on Windows NT 5.1 <X86> (Build 2600: Service Pack 3)
--  Subject: BOM按节点排序应用实例
--------------------------------------------------------------------------

--实例1:
--> 生成测试数据表:tb

IF NOT OBJECT_ID('[tb]') IS NULL
DROP TABLE [tb]
GO
CREATE TABLE [tb]([id] INT,[code] NVARCHAR(10),[pid] INT,[name] NVARCHAR(10))
INSERT [tb]
SELECT 1,'01',0,N'服装' UNION ALL
SELECT 2,'01',1,N'男装' UNION ALL
SELECT 3,'01',2,N'西装' UNION ALL
SELECT 4,'01',3,N'全毛' UNION ALL
SELECT 5,'02',3,N'化纤' UNION ALL
SELECT 6,'02',2,N'休闲装' UNION ALL
SELECT 7,'02',1,N'女装' UNION ALL
SELECT 8,'01',7,N'套装' UNION ALL
SELECT 9,'02',7,N'职业装' UNION ALL
SELECT 10,'03',7,N'休闲装' UNION ALL
SELECT 11,'04',7,N'西装' UNION ALL
SELECT 12,'01',11,N'全毛' UNION ALL
SELECT 13,'02',11,N'化纤' UNION ALL
SELECT 14,'05',7,N'休闲装'
GO
--SELECT * FROM [tb]

-->SQL查询如下:

;WITH T AS
(
SELECT CAST(CODE AS VARCHAR(20)) AS CODE,*,
CAST(ID AS VARBINARY(MAX)) AS px
FROM tb AS A
WHERE NOT EXISTS(SELECT * FROM tb WHERE id=A.pid)
UNION ALL
SELECT CAST(B.CODE+A.CODE AS VARCHAR(20)),A.*,
CAST(B.px+CAST(A.ID AS VARBINARY) AS VARBINARY(MAX))   
FROM tb AS A
JOIN T AS B
ON A.pid=B.id
)
SELECT Code,Name FROM T
ORDER BY px
/*
Code                 Name
-------------------- ----------
01                   服装
0101                 男装
010101               西装
01010101             全毛
01010102             化纤
010102               休闲装
0102                 女装
010201               套装
010202               职业装
010203               休闲装
010204               西装
01020401             全毛
01020402             化纤
010205               休闲装

(14 行受影响)
*/

--实例2:
--> 生成测试数据表:tb
IF NOT OBJECT_ID('[tb]') IS NULL
DROP TABLE [tb]
GO
CREATE TABLE [tb]([id] INT,[parentid] INT,[categoryname] NVARCHAR(10))
INSERT [tb]
SELECT 1,0,'test1' UNION ALL
SELECT 2,0,'test2' UNION ALL
SELECT 3,1,'test1.1' UNION ALL
SELECT 4,2,'test2.1' UNION ALL
SELECT 5,3,'test1.1.1' UNION ALL
SELECT 6,1,'test1.2'
GO
--SELECT * FROM [tb]
-->SQL查询如下:
;WITH T AS
(
SELECT *,CAST(ID AS VARBINARY(MAX)) AS px
FROM tb AS A
WHERE NOT EXISTS(SELECT * FROM tb WHERE id=A.[parentid])
UNION ALL
SELECT A.*,CAST(B.px+CAST(A.ID AS VARBINARY) AS VARBINARY(MAX))  
FROM tb AS A
JOIN T AS B
ON A.[parentid]=B.id
)
SELECT [id],[parentid],[categoryname] FROM T
ORDER BY px
/*
id          parentid    categoryname
----------- ----------- ------------
1           0           test1
3           1           test1.1
5           3           test1.1.1
6           1           test1.2
2           0           test2
4           2           test2.1
(6 行受影响)
*/

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