建立三个表:
create table t1
(id integer primary key,
num integer not null,
word1 text not null,
word2 text not null);
create table t2
(id integer primary key,
num integer not null,
word1 text not null,
word2 text not null);
create table t3
(id integer primary key,
num integer not null,
word1 text not null,
word2 text not null);
建立若干索引:
t1表:在num,word1,word2上有复合索引
t2表:在num,word1,word2上各有一个索引
t3表:在word1上有一个索引
create index idxT1 on t1(num,word1,word2);
create index idxT2Num on t2(num);
create index idxT2Word1 on t2(word1);
create index idxT2Word2 on t2(word2);
create index idxT3Word1 on t2(word1);
速度测试结果:
1) select count(*) from t1,t3 where t1.word2=t3.word2;
很慢(t3.word2上没有索引)
2) select count(*) from t3,t1 where t1.word2=t3.word2;
很慢(t1.word2上没有独立索引)
3) select count(*) from t1,t2 where t1.word2=t2.word2;
很快(t2.word2上有索引)
4) select count(*) from t2,t1 where t1.word2=t2.word2;
很慢(t1.word2上没有独立索引)
5) select count(*) from t1,t2 where t1.num=t2.num;
很快(t2.num上有索引)
6) select count(*) from t2,t1 where t1.num=t2.num;
很快(t1的复合索引中,第一个列是num)
7) select count(*) from t1,t3 where t1.num=t3.num;
很慢(t3.num上没有索引)
8) select count(*) from t3,t1 where t1.num=t3.num;
很快(t1的复合索引中,第一个列是num)