【趣味shell&python】倒三角控制台输出图形

jane27

　　通过脚本实现如下效果

1，python实现

#!/usr/bin/python
# filename:demo.py
# -*- coding: UTF-8 -*-
if __name__ == '__main__':
n = 20
for i in range(1, n):
m = i * 2 - 1
char1 = " "
char2 = "*"
print char1 * (n-i), char2*m

　　

2，shell实现一

#!/bin/sh
n=20
i=0
char1=" "
char2="*"
while [ $i -lt $n ];do
m=$(($i*2-1))
j=$(($n-$i))
while [ $j -gt 0 ]; do
echo -n "$char1"
j=$((j-1))
done
while [ $m -gt 0 ]; do
echo -n "$char2"
m=$((m-1))
done
echo ""
i=$((i+1))
done
exit 0

　　

3，shell实现二

#!/bin/bash
for i in $(seq 1 $1)
do
for j in $(seq 1 $(($1-$i)))
do
echo -n " "
done
for m in $(seq 1 $((2*$i-1)))
do
echo -n "*"
done
echo
done
exit 0

　　

4，shell实现三

#!/bin/bash
for i in $(seq 1 20)
do
for x in $(seq 1 $((5-$i)) )
do
echo -n " "
done
for y in $(seq 1 $(($i*2-1 )) )
do
echo -n "*"
done
echo
done
exit 0