Python核心编程（第二版）课后习题部分代码（5章）（持续更新）

黄智勇

本人近期研究了下Python，所用的书籍主要是Python核心编程（第二版）等，在此期间，我对书后的习题（编码部分）进行了实现，由于此书课后没有答案（英文版的答案也不全，我看的是电子书，不知道买的书后有没有答案），所以，在此把我的实现分享一下，希望对初学者有帮助。由于本人水平有限，在实现的编码中肯定有不合理的地方，希望大虾指出，我及时更正，大家共同交流。
5_2_return_Product

'''
@author: Riquelqi
'''
def return_Product(x,y):
print "'",x,"' multiply '",y ,"' equal" ,
return x*y
if __name__ == '__main__':
print return_Product(1, 2)

5_3_attainment_Test

'''
@author: Riquelqi
'''
def attainment_Test(x):
if x<0 or x>100 :
print 'It is a invalid number!'
elif x<60:
print "F"
elif 60<= x <=69:
print"D"
elif 70<= x <=79:
print 'C'
elif 80<= x <=89:
print 'B'
else :
print 'A'
if __name__ == '__main__':
attainment_Test(60)

5_4_leap_year_Test

'''
@author: Riquelqi
'''
def leap_year_Test(x):
if not isinstance(x,(int,long)):
print 'It is not a year!'
else :
if not x%4:
if not x%100:
print 'The year ',x,' is a leap year'
else :
print 'The year',x,'is not a leap year!'
if __name__ == '__main__':
leap_year_Test(2400)

5_5_coin_Convert

'''
@author: Riquelqi
'''
#The parameter x represent dollar
def coin_Convert(x):
aDollar=x*100
if aDollar<5:
print below_5_cent(aDollar)
elif aDollar<10:
print above_5_below_10_cent(aDollar)
elif aDollar<25:
print above_10_below_25_cent(aDollar)
else:
print above_twenty_five_cent(aDollar)
def below_5_cent(x):
return x,'coin of one cent!'
def above_5_below_10_cent(x):
return '1 coin of five cent and ',x%5,'coin of one coin'
def above_10_below_25_cent(x):
result_Tuple=divmod(x, 10)
temp=0
if result_Tuple[1]<5:
temp=below_5_cent(result_Tuple[1]),
else:
temp=above_5_below_10_cent(result_Tuple[1]),
return result_Tuple[0],'coin of ten cent and ',temp ,
def above_twenty_five_cent(x):
result_Tuple=divmod(x, 25)
temp=0
if result_Tuple[1]>10:
temp=above_10_below_25_cent(result_Tuple[1])
elif result_Tuple[1]>5:
temp=above_5_below_10_cent(result_Tuple[1])
else:
temp=below_5_cent(result_Tuple[1])
return result_Tuple[0],'coin of twenty-five cent and ',temp
if __name__ == '__main__':
coin_Convert(0.76)

5_6_calculator_implement

'''
@author: Riquelqi
'''
#       >>> a='1.0+2.0'
#       >>> a  
#       >>> '1.0+2.0'      
#       >>> b=a.count('.',0,len(a))
#       >>> b   
#       >>> 2
#            
def calculator_implement(x):
if x.count('**',0,len(x)):
q_list=x.split('**')
if x.count('.',0,len(x)):
return float(q_list[0])**float(q_list[1])
else:
return int(q_list[0])**int(q_list[1])
else:
#if expression contains a float
if x.count('.',0,len(x)):
if x.count('+',0,len(x)):
q_list=x.split('+')
return float(q_list[0])+float(q_list[1])
elif x.count('*',0,len(x)):
q_list=x.split('*')
return float(q_list[0])*float(q_list[1])
elif x.count('-',0,len(x)):
q_list=x.split('-')
return float(q_list[0])-float(q_list[1])   
elif x.count('/',0,len(x)):
q_list=x.split('/')
return float(q_list[0])/float(q_list[1])
elif x.count('%',0,len(x)):
q_list=x.split('%')
return float(q_list[0])%float(q_list[1])
else:
return'operator ERROR!'
else:
q_operator=x[1]
q_list=x.split(q_operator)
if '+' ==q_operator:
return int(q_list[0])+int(q_list[1])
elif '*'==q_operator:
return int(q_list[0])*int(q_list[1])
elif '-'==q_operator:
return int(q_list[0])-int(q_list[1])   
elif '/'==q_operator:
return  int(q_list[0])/int(q_list[1])
elif '%'==q_operator:
return int(q_list[0])%int(q_list[1])
else:
return'operator ERROR!'
if __name__ == '__main__':
input_str=raw_input('Please input a expression:')
result=calculator_implement(input_str)
print result

5_7_calculate_Tax

'''
@author: Riquelqi
'''
from decimal import Decimal
def calculate_Tax(x):
return Decimal(x)*Decimal('0.17')
if __name__ == '__main__':
input_operand=raw_input('Please input a operand:')
result=calculate_Tax(input_operand)
print result