sql server 查询本周、本月所有天数的数据

宇文氏

　　查询本月所有的天数：




select convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) day from
(select substring(convert(varchar,GETDATE(),120),1,7)+'-01' day) t1,
(select number from MASTER..spt_values WHERE TYPE='P' AND number>=0 and number<=31) t2
where convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) like substring(convert(varchar,GETDATE(),120),1,7)+'%'
　　查询本周所有的天数：



select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 0),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 1),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 2),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 3),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 4),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 5),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 6),120)
　　
示例：
　　如下图所示，有表MO_Orders，字段：BookTime,Number,Count，有如下数据。
　　
　　查询出本周的每天的数据总和，语句如下：



with t as
(
select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 0),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 1),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 2),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 3),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 4),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 5),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 6),120)
)
select id=ROW_NUMBER()OVER(ORDER BY t1.date),
DATENAME(weekday,t1.date) as weekday,
t1.date,
Numbers=sum(isnull(t2.Number,0)),  
Count=sum(isnull(t2.Count,0))
from t t1
left join
(  
select substring(convert(varchar,BookTime,120),1,11) as BookTime,
Number,Count
from  MO_Orders
where datediff(wk,BookTime-1,getdate()) = 0  
)
t2
on t1.date= substring(convert(varchar,t2.BookTime,120),1,11)
group by t1.date
　　查询效果如下图，其中 weekday为星期，此图还需替换，稍后补上：

　　示例：如下图所示，有表： MO_Orders，字段：BookTime，Cost，Count 。
　　查询本月的所有数据总和(其中：total=Cost*Count)。

　　查询出本月的每天的数据总和，显示每天的，查询语句如下：



with t as
(
select convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) date from
(select substring(convert(varchar,GETDATE(),120),1,7)+'-01' day) t1,
(select number from MASTER..spt_values WHERE TYPE='P' AND number>=0 and number<=31) t2
where convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) like substring(convert(varchar,GETDATE(),120),1,7)+'%'
)
select id=ROW_NUMBER()OVER(ORDER BY t1.date),
t1.date,
CostTotal=sum(isnull(t2.CostTotal,0))
from t t1
left join
(   
select BookTime,sum(CostTotal) as CostTotal from
(
select substring(convert(varchar,BookTime,120),1,11) as BookTime,
Cost*Count as CostTotal
from  MO_Orders
where datediff(month,BookTime,getdate()) = 0
) o group by BookTime
) t2
on t1.date= t2.BookTime
group by t1.date
　　查询结果如下图：