python:将数字转换成用英文表达的程序

heberoxx

　　前几天无意中看到了一篇文章列了很多数字的英文表达方式(http://blog.csdn.net/sun7545526/article/details/8122416),正好这段时间在学习python,所以写了个简单的程序用来将数字翻译成英文的表达方式,例如输入123,返回 one hundred and twenty-three
,目前该程序可以表示的范围为0-999,999,999,999.由于本人是个python新手,所以如果用的不完善的地方,还请帮忙改正
　　


'''
convert number to string, number range is 0-999,999,999,999 and must be integer
Created on 2012-10-31
@author: Eric
'''
import locale;
NUMBER_CONSTANT = {0:"zero ", 1:"one", 2:"two", 3:"three", 4:"four", 5:"five", 6:"six", 7:"seven",
8:"eight", 9:"nine", 10:"ten", 11:"eleven", 12:"twelve", 13:"thirteen",
14:"fourteen", 15:"fifteen", 16:"sixteen", 17:"seventeen", 18:"eighteen", 19:"nineteen" };
IN_HUNDRED_CONSTANT = {2:"twenty", 3:"thirty", 4:"forty", 5:"fifty", 6:"sixty", 7:"seventy", 8:"eighty", 9:"ninety"}
BASE_CONSTANT = {0:" ", 1:"hundred", 2:"thousand", 3:"million", 4:"billion"};
#supported number range is 1-n billion;
def translateNumberToEnglish(number):
if str(number).isnumeric():
if str(number)[0] == '0' and len(str(number)) > 1:
return translateNumberToEnglish(int(number[1:]));
if int(number) < 20:
return NUMBER_CONSTANT[int(number)];
elif int(number) < 100:
if str(number)[1] == '0':
return IN_HUNDRED_CONSTANT[int(str(number)[0])];
else:
return IN_HUNDRED_CONSTANT[int(str(number)[0])] + "-" + NUMBER_CONSTANT[int(str(number)[1])];
else:
locale.setlocale(locale.LC_ALL, "English_United States.1252");
strNumber = locale.format("%d"    , number, grouping=True);
numberArray = str(strNumber).split(",");
stringResult = "";
groupCount = len(numberArray) + 1;
for groupNumber in numberArray:
if groupCount > 1 and groupNumber[0:] != "000":
stringResult += str(getUnderThreeNumberString(str(groupNumber))) + " ";
else:
break;
groupCount -= 1;
if groupCount > 1:
stringResult += BASE_CONSTANT[groupCount] + ",";
endPoint = len(stringResult) - len(" hundred,");
#return stringResult[0:endPoint];
return stringResult;
else:
print("please input a number!");
#between 0-999
def getUnderThreeNumberString(number):
if str(number).isnumeric() and len(number) < 4:
if len(number) < 3:
return translateNumberToEnglish(int(number));
elif len(number) == 3 and number[0:] == "000":
return " ";
elif len(number) == 3 and number[1:] == "00":
return NUMBER_CONSTANT[int(number[0])] + "  " + BASE_CONSTANT[1];
else:   
return NUMBER_CONSTANT[int(number[0])] + "  " + BASE_CONSTANT[1] + " and " + translateNumberToEnglish((number[1:]));
else:
print("number must below 1000");

def testTranslateNumberToEnglish():
print("0: " + translateNumberToEnglish(0));
print("9: " + translateNumberToEnglish(9));
print("33: " + translateNumberToEnglish(33));
print("40: " + translateNumberToEnglish(40));
print("100: " + translateNumberToEnglish(100));
print("103: " + translateNumberToEnglish(103));
print("123: " + translateNumberToEnglish(123));
print("1,121,912  " + translateNumberToEnglish(1121912));
print("211,121,900  " + translateNumberToEnglish(211121900));
print("11,000,000  " + translateNumberToEnglish(11000000));
print("1,111,121,912  " + translateNumberToEnglish(111121912));
print("2,211,121,900  " + translateNumberToEnglish(2211121900));
print("1,111,000,000  " + translateNumberToEnglish(1111000000));
if __name__ == '__main__':
testTranslateNumberToEnglish();


　　输出的结果为:
　　0: zero

9: nine

33: thirty-three

40: forty

100: one hundred

103: one hundred and three

123: one hundred and twenty-three

1,121,912 one million,one hundred and twenty-one thousand,nine hundred and twelve

211,121,900 two hundred and eleven million,one hundred and twenty-one thousand,nine hundred

11,000,000 eleven million,

1,111,121,912 one hundred and eleven million,one hundred and twenty-one thousand,nine hundred and twelve

2,211,121,900 two billion,two hundred and eleven million,one hundred and twenty-one thousand,nine hundred

1,111,000,000 one billion,one hundred and eleven million,