08: value too great for base (error token is "08")的shell进制问题

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.html　　原因：以下是代码片段：
　　Numbers starting with leading 0 are Octal numbers (base 8) in many programming
　　languages including C, Perl and shell. Valid octal digits are
　　0,1,2,3,4,5,6,7 so it barfs if it sees an 8 or a 9. You probably want
　　to work in straight numbers and make a leading 0 in your output
　　format with a sprintf("d") kind of formatting thing.
　　Anything starting with 0x or 0X is a hex number.
　　So the error message means exactly as it says- it's an error from
　　the let function complaining about the value being too big for the base.
　　上面就是说以0开头的被默认为八进制了，所以08就是无效的八进制数喽，呵呵
　　解决方案：以下是代码片段：
　　You can explicitly state the base of a number using base#number
　　Code:
　　if [ $((10#$item)) -eq 0 ] ; then
　　That will have trouble if the number starts with a minus sign.
　　The '-' needs to be in front of the base like -10#009 for -9.
　　上面就是说解决方法可以用 进制#变量 来转换，如08 改成10进制 10#08 或 10#$var ,
　　还有就是关于负号 - 要放在前面 -10#08